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3 years ago

What is the point of maximum growth:

Mathematics

1 answer:

salantis [7]3 years ago

7 0

f(h(x))= 2x -21

Step-by-step explanation:

f(x)= x^3 - 6

h(x)=\sqrt[3]{2x-15}

WE need to find f(h(x)), use composition of functions

Plug in h(x)

f(h(x))=f(\sqrt[3]{2x-15})

Now we plug in f(x) in f(x)

f(h(x))=f(\sqrt[3]{2x-15})=(\sqrt[3]{2x-15})^3 - 6

cube and cube root will get cancelled

f(h(x))= 2x-15 -6= 2 x-21

wait i think i did the wrong one brb

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A car travels 20 1/2 miles in 2/3 of an hour. What is the average speed, in miles per hour, of thr car?

zmey [24]

Answer:

27.33333... mph

Step-by-step explanation:

Find 1/3 of 20 1/2: 1/3*41/2=41/6

That equals 6.83333...

Now add 20 1/2 and 6.83333 = 27.3333...

Therefore, 27.33333... mph

3 0

2 years ago

How to find imaginary zeros anf real zeros of F(x)=-4x^5-8x^3+12x

Fofino [41]

Answer:

$x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}$

Step-by-step explanation:

We are given the function:

$f(x)=-4x^5-8x^3+12x$

And we want to finds its zeros.

Therefore:

$0=-4x^5-8x^3+12x$

Firstly, we can divide everything by -4:

$0=x^5+2x^3-3x$

Factor out an x:

$0=x(x^4+2x^2-3)$

This is in quadratic form. For simplicity, we can let:

$u=x^2$

Then by substitution:

$0=x(u^2+2u-3)$

Factor:

$0=x(u+3)(u-1)$

Substitute back:

$0=x(x^2+3)(x^2-1)$

By the Zero Product Property:

$x=0\text{ and } x^2+3=0\text{ and } x^2-1=0$

Solving for each case:

$x=0\text{ and } x=\pm\sqrt{-3}\text{ and } x=\pm\sqrt{1}$

Therefore, our real and complex zeros are:

$x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}$

4 0

2 years ago

X + 5y = 28<br> - x - 2y = -13

bazaltina [42]

Answer:

x=3

y=5

Step-by-step explanation:

x+5y=28 (i)

-x-2y=-13. (ii)

add equation 2 from equation 1

x+5y=28

-x-2y=-13

3y=15

y=5

put the value of y in equation 1

x+5y=28

x+5*5=28

x+25=28

x=28-25

x=3

8 0

3 years ago

Write an equivalent expression for 5a+30

Elena-2011 [213]

We can express it at 5 (a+6)

7 0

3 years ago

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What is the correct factorization of x2 5x – 6? (x – 1) (x 6) (x 1) (x – 6) (x – 2) (x – 3) (x – 2) (x 3)

gulaghasi [49]

I hope this helps you

x^2-5x-6

x -6

x +1

(x-6)(x+1)

x^2+5x-6

x +6

x -1

(x+6)(x-1)

5 0

3 years ago

Read 2 more answers