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arlik [135]
3 years ago
5

Five people each write a positive integer on a piece of paper. If the average of these five integers is 8, what is the greatest

possible value of one of these integers?
A. 36
B. 38
C. 39
D. 40
Mathematics
2 answers:
frozen [14]3 years ago
8 0

Answer: 36

Step-by-step explanation:

erik [133]3 years ago
6 0

Answer:

Option D. 40

Step-by-step explanation:

Let

x------>the greatest possible value  

we know that

If four people write the number zero, then the average will be

8=(0+0+0+0+x)/5\\ \\40=0+x\\ \\x=40

You might be interested in
3x – 9y = -39<br> -3x – 7y = -25 systems of elimination
photoshop1234 [79]

Answer:

y= 4 , x= -1

Step-by-step explanation:

3x-9y= -39

-3x-7y= -25

-16y= -64

y= -64/-16

y= 4

substitute y into any equation

3x -9(4) = -39

3x-36= -39

3x= -39+36

3x= -3

x= -3/3

x= -1

7 0
3 years ago
What is the answer?
Dmitrij [34]

Answer:

read explanation

Step-by-step explanation:

rearrange equations to form y=mx+b

-2x+4=2y

-x+2=y

-y=-2x-5

y=2x+5

use these equations to find slope and y intercepts, and match those with the right graph

slope of first: -1

slope of second: 2

y-int of first: 2

y-int of second:5

3 0
3 years ago
Name two different numbers that round to 30 when rounded to the nearest ten
andrew11 [14]

For this case we have the following definition:

tens place: number of two digits whose absolute value is greater than zero.

Then, we have the following rounding rule:

If the previous number is greater than or equal to five, the next number increases by one unit.

We then have the following numbers rounded to 30 when rounded to the nearest ten:

26: twenty-six

27: twenty-seven

Answer:

two different numbers that round to 30 when rounded to the nearest ten are:

26: twenty-six

27: twenty-seven

6 0
3 years ago
Read 2 more answers
Compare -6/11 -2/3 ^ = ^
nignag [31]

Answer:

-40/33

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
PLZ HELP ASAP!!!!<br><br> Solve for X:<br> 2X^3 = 54
mariarad [96]
X=3

Divide both sides of the equation by 2
X^3 =27

Write the number in exponential form with an exponent of 3
X^3=3^3

Since the exponents are the same, set the bases equal
X=3
6 0
3 years ago
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