Question

Can someone help me with this two problems?

Answer 1

2x+4y=0

substitute y with 0

2x+4(0)=0

solve the equation

2x+0=0

2x=0

divide by 2 on both sides

x=0

4x+8y=7

substitute y with 0

4x+8(0)=7

solve the equation

4x+0=7

4x=7

divide by 4 on both sides

x=7/4 or x=1 3/4 or x=1.75

3x-7y=-29

2x+2y=6

solve the bottom equation

3x-7y=-29

x=3-y

substitute for x

3(3-y)-7y=-29

solve the equation

y=19/5

now substitute for y

x=3-$\frac{19}{5}$

solve for x

x=-4/5

the possible solution of the system is the ordered pair

(x,y)=($-\frac{4}{5} ,\frac{19}{5}$)