Power property:
![log_{a} b^m=m \cdot log_a b](https://tex.z-dn.net/?f=log_%7Ba%7D%20b%5Em%3Dm%20%5Ccdot%20log_a%20b)
That means the power m can be brought down to front of the logarithm.
Using the power property, we get
If anything is in parentheses do that first, however if there isn’t you always do exponents next so evaluate 6 squared
Hope this helps!!
Answer:
Therefore the equation of the line through ( -7 , 5 ) and ( -5 , 9) is
Linear Relationship i.e ![y-5=2(x+7)](https://tex.z-dn.net/?f=y-5%3D2%28x%2B7%29)
Step-by-step explanation:
Given:
Let,
point A( x₁ , y₁) ≡ ( -7, 5 )
point B( x₂ , y₂) ≡ (-5, 9)
To Find:
Equation of Line AB =?
Solution:
Equation of a line passing through Two points A( x₁ , y₁) and B( x₂ , y₂)is given by the formula
![(y - y_{1} )=(\frac{y_{2}-y_{1} }{x_{2}-x_{1} })\times(x-x_{1}) \\](https://tex.z-dn.net/?f=%28y%20-%20y_%7B1%7D%20%29%3D%28%5Cfrac%7By_%7B2%7D-y_%7B1%7D%20%7D%7Bx_%7B2%7D-x_%7B1%7D%20%7D%29%5Ctimes%28x-x_%7B1%7D%29%20%5C%5C)
Substituting the given values in a above equation we get
![(y-(5))=(\frac{9-(5)}{-5--7})\times (x--7)\\ \\(y-5)=\frac{4}{2}(x+7)\\\\y-5=2(x+7)...............\textrm{which is the required equation of the line AB}](https://tex.z-dn.net/?f=%28y-%285%29%29%3D%28%5Cfrac%7B9-%285%29%7D%7B-5--7%7D%29%5Ctimes%20%28x--7%29%5C%5C%20%5C%5C%28y-5%29%3D%5Cfrac%7B4%7D%7B2%7D%28x%2B7%29%5C%5C%5C%5Cy-5%3D2%28x%2B7%29...............%5Ctextrm%7Bwhich%20is%20the%20required%20equation%20of%20the%20line%20AB%7D)
Therefore the equation of the line through ( -7 , 5 ) and ( -5 , 9 ) is
Linear Relationship i.e ![y-5=2(x+7)](https://tex.z-dn.net/?f=y-5%3D2%28x%2B7%29)
Answer:
X<-3
Step-by-step explanation: