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Morgarella [4.7K]
3 years ago
5

n circle O, and are diameters. Arc ED measures 17°. Circle O is shown. Line segments F C and A E are diameters. Line segments C

O and B O are radii. Point B is between points A and C, and point C is between points E and C. Angle D C is a right angle. What is the measure of Arc E F C?
Mathematics
1 answer:
ella [17]3 years ago
8 0

Answer:

C. 253

Step-by-step explanation:

add the two angles known to get 107.

then subtract that from 360. You will get 253

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Two angles of a quadrilateral measure 325° and 10°. The other two angles are in a ratio of 2:3. What are the measures of those t
Dmitry_Shevchenko [17]

Answer:

The answer is 60 and 80

Step-by-step explanation:

7 0
3 years ago
write the ratio as a percent 6 per 100 , 49 out of 100 , 16 per 100 , 21 out of 100 , 80 per 100 , 93 out of 100​
DedPeter [7]

Answer:

6%, 49%, 16%, 21%, 80%, 93%

Step-by-step explanation:

add the percent sign to each each number (6, 49, 16, 21, 80, and 93).

6 0
4 years ago
Read 2 more answers
What is the lcm for 3/4and 1/2​
ioda

Answer:

1 1/2

Hope that helps!

Step-by-step explanation:

4 0
3 years ago
Find two unit vectos that are orthogonal to both [0,1,2] and [1,-2,3]
alekssr [168]

Answer:

Let the vectors be

a = [0, 1, 2] and

b = [1, -2, 3]

( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.

Let the cross product be another vector c.

To find the cross product (c) of a and b, we have

\left[\begin{array}{ccc}i&j&k\\0&1&2\\1&-2&3\end{array}\right]

c = i(3 + 4) - j(0 - 2) + k(0 - 1)

c = 7i + 2j - k

c = [7, 2, -1]

( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:

c / | c |

Where | c | = √ (7)² + (2)² + (-1)²  = 3√6

Therefore, the unit vector is

\frac{[7,2,-1]}{3\sqrt{6} }

or

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

In conclusion, the two unit vectors are;

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

and

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

<em>Hope this helps!</em>

7 0
3 years ago
The price of gasoline at a service station increased from $1.65 per gallon last week to $1.82 per gallon this week. Sally paid $
Mila [183]

Answer:

  $2.72

Step-by-step explanation:

The increase from last week is the fraction ...

  (new price)/(old price) -1 = (1.82/1.65) -1 = 17/165

so the amount of increase Sally will pay this week is ...

  17/165×$26.40 = $2.72

_____

<em>Comment on the working</em>

We could work this several ways. Perhaps most straightforward would be to determine how many gallons Sally bought last week, and multiply that by the change in price. Or, the number of gallons could be multiplied by the new price per gallon and the difference from the old purchase amount found.

If you look at the numbers, you see that we have effectively done it the first way. The change in price is $0.17 per gallon, and the number of gallons Sally bought is $26.40/$1.65.

8 0
3 years ago
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