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3 years ago

In 56 years,Kevin will be 9 times as old as he is right now . How old is he right now ?

2 answers:

8 0

6 bc if you divide 56 by 9 you’ll get 6.2 but i’m not sure the ( .2 ) will matter therefore just get the first digit which is 6

Zanzabum3 years ago

8 0

Answer:

Kevin is 7

Step-by-step explanation:

In 56 years if Kevin is 7 now he will be 63 and 7X9 = 63

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P l e a s e h e l p p p p !!!

Mandarinka [93]

Answer:

This would be the last option I think, sorry if it's wrong.

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The lengths of two sides of a right triangle are 12 inches and 15 inches. What is the difference between the two possible length

Lena [83]

In the problem, two legs measurement were given such as:
Leg 1 = 12 inches
Leg 2 = 15 inches

We need to solve for the third leg. Since it is a right triangle, we can use Pythagorean theorem in solving the missing leg:
c²=b²+a²

When we assume that the third leg is the "c", we can for the value such as:
c² = 12²+15²
c=19.21

When we assume that the third is either "a" or "b":
15² =a² + 12²
a=9

Then, the possible measurement of the third leg is 9 or 19.21.
The difference between the two possible answer is shown below:
Difference = 19.21 -9 = 10.21
Difference =10.21

6 0

3 years ago

A: 1/2 inch <br> B: 1 inch <br> C: 2 inches<br> D: 1/32 inch

mote1985 [20]

The expression of the height is

$a_n=8\cdot (\frac{1}{2})^{n-1}$

the index "n" is the numbers of times that the ball is down, to n=1 the height is 8 inches, to n=2 the height is 4 inches.

An when n=5, the height is

$a_5=8\cdot (\frac{1}{2})^{5-1}=8\cdot (\frac{1}{2})^4=\frac{1}{2} =0.5$

the anwers is 0.5 inches

4 0

3 years ago

For which value of x( from 1 to 10) is y the greatest?

qwelly [4]

10 i think..... plz don't report me

4 0

3 years ago

Help me complete this

frutty [35]

Answer:

x = 9.9 in.

Step-by-step explanation:

area of triangle = base * height /2

49 = x*x /2

49*2 = x^2

98 = x^2

$\sqrt{98}$ = x

$7\sqrt{2}$ = x

9.9 = x

3 0

2 years ago