All categories

3 years ago

In 56 years,Kevin will be 9 times as old as he is right now . How old is he right now ?

2 answers:

8 0

6 bc if you divide 56 by 9 you’ll get 6.2 but i’m not sure the ( .2 ) will matter therefore just get the first digit which is 6

Zanzabum3 years ago

8 0

Answer:

Kevin is 7

Step-by-step explanation:

In 56 years if Kevin is 7 now he will be 63 and 7X9 = 63

You might be interested in

Which expression is equivalnt (-18) - 64n

Naily [24]

Answer:

Your correct answer is option C. -2 (9 + 32n)

Step-by-step explanation:

Solution:

Options are not given in the question

Given First degree expression:

-18-64n

= (-2)×9 + (-2)×32n

Take (-2) common, we get

= (-2)( 9+32n)

Therefore you get your answer of option C. -2(9+32n)

8 0

3 years ago

Read 2 more answers

Dexter is curious as to whether there is a relationship between a person’s height and thumb length. Fourteen of his classmates v

love history [14]

The answer to this question is 7.404

3 0

3 years ago

This year, a small business had a total revenue of $45,000. If this is 25% less than their total revenue the previous year, what

morpeh [17]

Let R = total revenue the year before

R = 45,000 x 0.25 + 45,000

R = 11,250 + 45,000

R = $56,250

7 0

3 years ago

Stop only watching, and start writing dude. thanks

yanalaym [24]

I don't know but if I were to guess I'll pick C. Hope this helps

6 0

3 years ago

On your paper, construct a rectangle on a coordinate plane that satisfies these criteria.

german

Answer:

$A = (5,3)$

$B = (-5,3)$

$C = (-5,-8)$

$D = (5,-8)$

Step-by-step explanation:

Required

$Perimeter = 42$

Construct a rectangle whose perimeter is 42 units and satisfies the given conditions.

First, name the rectangle ABCD.

Such that:

$A = (x_1,y_1)$

$B = (x_2,y_2)$

$C = (x_3,y_3)$

$D = (x_4,y_4)$

For the rectangle to be either horizontal or vertical, then:

$y_1 = y_2$ and $y_3 = y_4$

We have that:

$Perimeter = 42$

Replace perimeter with its formula

$2(AB + BC) = 42$

Divide both sides by 2

$AB + BC = 21$

This implies that, the distance between adjacent sides (through the edges) must be equal to 21

Having said that: a set of coordinates that satisfy the given conditions are:

$A = (5,3)$ -- First quadrant

$B = (-5,3)$ -- Second quadrant

$C = (-5,-8)$ -- Third quadrant

$D = (5,-8)$ -- Fourth quadrant

The above quadrants satisfy the condition:

$y_1 = y_2$ and $y_3 = y_4$

HOW TO KNOW THE PERIMETER IS 42

To do this, we simply calculate the distance between the edges and add them up

Distance is calculated as:

$D = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2$

For AB

$A = (5,3)$

$B = (-5,3)$

$D_1 = \sqrt{(5 - (-5))^2 + (3 - 3)^2}= \sqrt{(10)^2 + (0)^2} = \sqrt{100} = 10$

For BC

$B = (-5,3)$

$C = (-5,-8)$

$D_2 = \sqrt{(-5 - (-5))^2 + (3 - (-8))^2}= \sqrt{(0)^2 + (11)^2} = \sqrt{121} = 11$

For CD

$C = (-5,-8)$

$D = (5,-8)$

$D_3 = \sqrt{(-5 -5)^2 + (-8 - (-8))^2}= \sqrt{(-10)^2 + (0)^2} = \sqrt{100} = 10$

For DA

$D = (5,-8)$

$A = (5,3)$

$D_4 = \sqrt{(5 -5)^2 + (-8 -3)^2}= \sqrt{(0)^2 + (11)^2} = \sqrt{121} = 11$

So, the perimeter is:

$P = D_1 + D_2 + D_3 + D_4$

$P = 10 + 11 + 10 +11$

$P = 42$

See attachment for rectangle

8 0

3 years ago