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Tatiana [17]
3 years ago
14

Carbon–14 is a radioactive isotope that decays exponentially at a rate of 0.0124 percent a year. How many years will it take for

carbon–14 to decay to 10 percent of its original amount? The equation for exponential decay is At = A0e–rt.
Mathematics
1 answer:
patriot [66]3 years ago
5 0
100-0.0124=99.9876

10%=1/10
1/10P=P(0.999876)^t
divide both sides by P
1/10=0.999876^t
take ln of both sides
ln(1/10)=t (ln(0.999876))
divide both sides by (ln(0.999876))
ln(1/10)/(ln(0.999876))=t
use calculator
18568.08=t
about 18568 years

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Answer:

a₈ = 37

Step-by-step explanation:

The given arithmetic sequence is: 3, 8, 13, 18, 23, . . .

The recursive formula for the sequence is: $ a_n = a_{n - 1} + 5 $

Here, $ a_n $ represents the $ n^{th} $ of the sequence.

And, $ a_{n - 1} $ represents the $ (n - 1)^{th} $ of the sequence.

'+5' denotes that '5' is added to the $ (n - 1)^{th} $ term to get the $ n^{th} $ term. In other words, the difference between two consecutive numbers in the sequence is 5.

Now, we are asked to find a₈ i.e., n =8.

Substituting in the recursive formula we get: a₈ = a₍₈₋ ₁₎ + 5 = a₇ + 5.

So, to determine a₈ we need to know a₇. From the sequence we see that a₅ = 23.

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Two linear equations are shown. A coordinate grid with 2 lines. The first line is labeled y equals StartFraction one-third EndFr
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Step-by-step explanation:

we have

<em>The equation of the first line</em>

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<em>The equation of the second line</em>

y=\frac{4}{3}x-5 ------> equation B

Solve the system of equations by elimination

Multiply equation A by -4 both sides

(-4)y=(-4)(\frac{1}{3}x+2)

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Adds equation B and equation C

y=\frac{4}{3}x-5\\-4y=-\frac{4}{3}x-8\\--------\\y-4y=-5-8\\-3y=-13\\y=\frac{13}{3}

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substitute the value of y

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\frac{1}{3}x=\frac{13}{3}-2

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x=13-6

x=7

therefore

The solution to the system of equations is the point (7,\frac{13}{3})

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