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Drupady [299]
3 years ago
7

Evaluate the expression using x = –1 and y=3. (6x4y3) What is the value of the expression? –162 –54 162 216

Mathematics
2 answers:
Wewaii [24]3 years ago
6 0
Subst. the given x and y values:  6(-1)^4 * (3)^3
                                                         6      * 27 = 162

Note that you MUST do the exponentiation first.

Also note that your post would be much clearer if you'd please use " ^ " to denote exponentiation:      6x^4 * y^3
Crank3 years ago
5 0

Answer:

c. 162

Step-by-step explanation:

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Sheila has 28 stickers to divide evenly among 3 friends. She thinks there will be no leftovers. Use what you know about factor p
zysi [14]

Answer:

She is wrong

Step-by-step explanation:

If our target number is 28 then we can create all of the following factor pairs for this number. These would be the following...

1, 2, 4, 7, 14 and 28

As we can see from the factor pairs there is no 3. This means that 3 would not divide evenly by 28 and cannot be multiplied by any whole number to create 28. Therefore, if you divide the 28 stickers by the 3 friends there will be some stickers leftover always.

4 0
2 years ago
How can you apply the distributive property to factor out the greatest common factor for 40j - 16 = ?
Ronch [10]
The greatest common factor is 8. So your answer would be: 8(5j - 2) because 8 x 5j= 40j and 8 x 2= 16 
6 0
3 years ago
Find Value of x and TS if T is between R and S.
Romashka-Z-Leto [24]

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3 years ago
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3 0
3 years ago
Read 2 more answers
1. Find the area of the region bounded above by y = e^x, bounded below by y = x, and bounded on the sides
salantis [7]

The area of the region bounded above by y= eˣ bounded by y = x, and bounded on the sides; x =0; and x = 1 is given as e¹ - 1.5.

<h3>What is the significance of "Area under the curve"?</h3>

This is the condition in which one process increases a quantity at a certain rate and another process decreases the same quantity at the same rate, and the "area" (actually the integral of the difference between those two rates integrated over a given period of time) is the accumulated effect of those two processes.

<h3>What is the justification for the above answer?</h3>

Area = \int\limits^1_0 {(e^x-x)} \, dx

= \int\limits^1_0 {e^x-x} \, dx - \int\limits^1_0 {(x)} \, dx

= e¹-(1/2-0); or

Area = e -1.5 Squared Unit

The related Graph is attached accordingly.

Learn more about area bounded by curve:
brainly.com/question/27866606
#SPJ1

3 0
1 year ago
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