Following PEMDAS is crucial to solving these. Please Excuse My Dear Aunt Sally
P - Parenthesis
E - Exponents
M - Multiplication
D - Division
A - Addition
S - Subtraction
Multiplication/Division and Addition/Subtraction are interchangeable.
Now then, number 1 has the following:

There are no parenthesis or exponents, but there is multiplication, so we will start with multiplying. There are two multiplication expressions in the problem.


Since you did that, your answer has been simplified to:

Now, all you have to do is combine your like terms. Since every term is alike, you can combine the whole expression.

So, your final answer would be:

Hopefully with this information, you can solve the rest. If you have any questions, let me know.
Hello from MrBillDoesMath!
Answer:
Choice A, 18x - 6y = 20
Discussion:
Given line
-9x + 3y = 12 (M)
Choice A:
18x - 6y = 20 => divide both sides by -2
-9x + 3y = -10 (N)
The left hand sides of (M) and (N) are equal implying that right hand sides are equal which further implies 12 = -10. Contradiction! so the system M and N has no solution.
Thank you,
MrB
Answer:
80 answer is 80
Step-by-step explanation:
50+30 = 80 answer
Answer:
2. The change in expected height for every one additional centimeter of femur length.
Step-by-step explanation:
<u>1. The expected height for someone with a femur length of 65 centimeters.</u>
<em>Doesn't make sense, that would be height value when centimeters = 65.</em>
<u>2</u><u><em>. </em></u><u>The change in expected height for every one additional centimeter of femur length.</u>
<em>Makes sense, for every increase in one additional centimeter, we can expect the height to be proportional to the slope.</em>
<u>3. The femur length for someone with an expected height of 2.5 centimeters.</u>
<em>Doesn't make sense, the linear relationship relies on the femur length to get the height.</em>
<u>4. The change in expected femur length for every one additional centimeter of height.</u>
<em>Doesn't make sense, again, the linear relationship relies on the femur length.</em>