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3 years ago

6

1. Use the sequence to answer the questions. 2.5, 6, 9.5, 13, 16.5, 20,… (a) What is the common difference? (b) What is the recu

rsive rule for the sequence?

1 answer:

aev [14]3 years ago

6 0

Common difference = 6 - 2.5 = 3.5

(B) recursive formula can be written as
U(n+1) = U(n) + 3.5n
where value of n is 0 to infinity

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Corrected Question

a. Develop a probability distribution for the job satisfaction score of a senior executive.

b. Develop a probability distribution for the job satisfaction score of a middle manager.

c. What is the probability a senior executive will report a job satisfaction score of 4 or 5?

d. What is the probability a middle manager is very satisfied?

Answer:

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(d)0.28

Step-by-step explanation:

The percent frequency distributions of job satisfaction scores os give below:

$\left|\begin{array}{c|c|c}$Job Satisfaction Score&$IS Senior Executives(\%)&$IS Middle Managers(\%)\\1&5&4\\2&9&10\\3&3&12\\4&42&46\\5&41&28\end{array}\right|$

(a)Probability distribution for the job satisfaction score of a senior executive.

$\left|\begin{array}{c|c}$Job Satisfaction Score&$Relative Frequency (f_1(x))\\------&------\\1&0.05\\2&0.09\\3&0.03\\4&0.42\\5&0.41\end{array}\right|$

(b)Probability distribution for the job satisfaction score of a middle manager.

$\left|\begin{array}{c|c}$Job Satisfaction Score&$Relative Frequency (f_2(x))\\1&0.04\\2&0.10\\3&0.12\\4&0.46\\5&0.28\end{array}\right|$

(c)Probability a senior executive will report a job satisfaction score of 4 or 5

P(a senior executive will report a job satisfaction score of 4 or 5)

$=f_1(4)+f_1(5)\\=0.42+0.41\\=0.83$

(d)Probability a middle manager is very satisfied

The probability a middle manager is very satisfied

$=f_2(5)\\=0.28$

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