If A=38x-x^2 then
dA/dx=38-2x
d2A/dx2=-2
Since the acceleration, d2A/dx2 is a constant negative, when velocity, dA/dx=0, it will be an absolute maximum for A(x)
dA/dx=0 only when 38=2x, x=19
A(19)=38(19)-19^2
A(19)=722-361
A(19)=361 ft^2
So the maximum possible area is 361 ft^2
(This will always be true as the maximum possible area enclosed by a given amount of material will always be a perfect square...)
Answer:
3
Step-by-step explanation:
Answers:
y = 50
angle AOB = 100
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Explanation:
Angle x is an inscribed angle that subtends or cuts off minor arc AB. This is the shortest distance from A to B along the circle's edge.
Angle y is also an inscribed angle that cuts off the same minor arc AB. Therefore, it is the same measure as angle x. We can drag point D anywhere you want, and angle y will still be an inscribed angle and still be the same measure as x.
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Point O is the center of the circle. This is because "circle O" is named by its center point.
Angle AOB is considered a central angle as its vertex point is the center of the circle.
Because AOB cuts off minor arc AB, and it's a central angle, it must be twice that of the inscribed angle that cuts off the same arc.
This is the inscribed angle theorem.
Using this theorem, we can say the following
central angle = 2*(inscribed angle)
angle AOB = 2*(angle x)
angle AOB = 2*50
angle AOB = 100 degrees
Answer:
fill in the missing number on the number line
2350 2350
