(-6)(-0.4)(-0.5) = (-1)6⋅4⋅5⋅10⁻² = -1.2
Answer:
6a) i- 2hrs 36mins ii- 3hrs 12mins
b) car A≈ 76.9km/h car B≈ 62.5km/h
c)------
7a) 35km
b) car A=75km car B=60km
c) 30km
d) car A≈36mins car B≈48mins
Step-by-step explanation:
6a) Using the graph follow the lines until they finish then go downwards until you get to the x-axis. The x-axis is going up by 12mins for each square.
b) Using the answer from a, you divide 200km by the time.
For car A 2hrs 36mins becomes 2.6 because 36mins/60mins=0.6
∴ car A: 200/2.6≈ 76.92km/h
For car B 3hrs 12mins becomes 3.2 because 12mins/60mins=0.2
∴ car B: 200/3.2≈ 62.5km/h
7a) Using the graph go down from where the line of car A finished to meet car B. The y-axis is going up by 5km for each square.
b) Starting from the x-axis at 1 hour go upwards to see where you meet the car B line (60km) and car A line(75km). (sorry if that does not really make sense).
c) Difference from car A line to car B:
155km-125km=30km
d) Going across from 50km meet car A line and go down to see it has been travelling for approx. 36mins. Then continue across to car B line, go down to see it reached 50km at approx. 48mins.
Hope this helps.
Answer:
<h2>F. 12</h2>
Step-by-step explanation:
The distance between A and M i.e JM = M - J = 5-(-19)
JM = 5+19
JM = 24
If JK:KL:KM = 2:1:3
The total ratio = 2+1+3
Total ratio = 6
Dividing each length based on ratio
length JK = 2/6 * JM
JK = 1/3 * 24
JK = 8
length KL = 1/6 * JM
KL = 1/6 * 24
KL = 4
length KM = 3/6 * JM
KM = 1/2 * 24
KM = 12
<em>Hence the value of KM is 12</em>
originally. Then you reduces the side lengths a so it will be
Just note that 40% is the same as 2/5.<span />
Answer:
y = 108x + 216
Step-by-step explanation:
given
y = 4x³ then 
= 12x² = 
x = 3 ⇒ m = 12(- 3)² = 108
equation of tangent in slope- intercept form is
y = mx + b ( m is the slope and b the y- intercept ), hence
y = 108x + b
To find b substitute (- 3, - 108) into the equation
- 108 = -324 + b ⇒ b = - 108 + 324 = 216
y = 108x + 216 ← equation of tangent
