Answer:
503 $1 tickets sold.
Step-by-step explanation:
Use two equations
Let x = number of $1 tickets sold
Let y = number of $1.50 tickets sold
x + y = 739
1x + (1.5)y = 857
First equation ==> y = 739 - x
Plug this into the second equation
x + (1.5)(739 - x) = 857
x + 1108.5 - 1.5x = 857
- 0.5x = -251.5
x = 503
There were 503 $1 tickets sold.
To find the number of $1.50 tickets, just plug this value of x into either one of the equations.
(503) + y = 739 (739 - 503 = 236)
y = 236
There were 236 $1.50 tickets sold.
I got 39 tables.
134+167=301
301/7=43
Total amount of people =344
344/9=38.222 which you would round to 39 tables
Solve for c :
x⁴ + cx² + 100 = 0
cx² = -(x⁴ + 100)
c = - (x⁴ + 100)/x²
If x = 0, the right side is undefined and c would have no solution.
First you have to make it multiplication so you flip 5/2 around and the two “2’s” will cancel each other so it will be 17/5 or 3 2/5