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Alex
3 years ago
6

A dilation produces a smaller figure. Which is a possible scale factor?

Mathematics
1 answer:
taurus [48]3 years ago
4 0

Answer:

The answer in the procedure

Step-by-step explanation:

we know that

If the dilation produces a smaller figure

then

the scale factor must be less than one

Let

z -----> the scale factor

z < 1

A possible scale factor can be 0.50, 0.20,0.35,0.80, etc

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3/x+3+2/x What is the common denominator in this rational expression? Answers should be given in fully factored form.
Inga [223]

Answer:

x(x+3).

Step-by-step explanation:

The C, D. of x and x+3 is x(x+3).

7 0
2 years ago
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kompoz [17]
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3 0
2 years ago
Read 2 more answers
21-m=9 anyone know this ?
prisoha [69]

Answer:

m=12

Step-by-step explanation:

21-m=9

-m=9-21

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m=12

6 0
3 years ago
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Julia enjoys shooting paper balls into the wastebasket across her office. She misses the first shot 50% of the time. When she mi
Marianna [84]

Answer:

a) Probability that Julia misses two shots in a row = \frac{1}{2}\frac{1}{5} =\frac{1}{10}

b) We can use the complement rule on this case. Let X the number of shoots successful, we want this probability:

P(X \geq 1)

And using the complement rule we have this:

P(X \geq 1) = 1-P(X

And P(X=0) correspond to the probability that Julia misses two shots in a row founded on part A so then we have:

P(X\geq 1) = 1- \frac{1}{10}= \frac{9}{10}

Step-by-step explanation:

Part a

For this case we know that Julia enjoys shooting paper balls into the basket across her office.

She misses the first shot 50% of the time.

Probability that Julia misses the first shot = \frac{1}{2}

When she misses on the first shot, she misses the second shot 20% of the time.

Probability that Julia misses the second shot = \frac{1}{5}

For this case we need to find the probability of missing two shots in a row

So we can multiple the two probabilities like this

Probability that Julia misses two shots in a row = \frac{1}{2}\frac{1}{5} =\frac{1}{10}

Part b

For this case we want probability of making at least one successful throw

And we can use the complement rule on this case. Let X the number of shoots successful, we want this probability:

P(X \geq 1)

And using the complement rule we have this:

P(X \geq 1) = 1-P(X

And P(X=0) correspond to the probability that Julia misses two shots in a row founded on part A so then we have:

P(X\geq 1) = 1- \frac{1}{10}= \frac{9}{10}

6 0
3 years ago
Write an expression for the operation below. s subtract 8.​
soldi70 [24.7K]

Answer:

S - 8

Step-by-step explanation:

S - 8.

hope this helps! Have a great day!

8 0
2 years ago
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