<h2>
Maximum area is 25 m²</h2>
Explanation:
Let L be the length and W be the width.
Aidan has 20 ft of fence with which to build a rectangular dog run.
Fencing = 2L + 2W = 20 ft
L + W = 10
W = 10 - L
We need to find what is the largest area that can be enclosed.
Area = Length x Width
A = LW
A = L x (10-L) = 10 L - L²
For maximum area differential is zero
So we have
dA = 0
10 - 2 L = 0
L = 5 m
W = 10 - 5 = 5 m
Area = 5 x 5 = 25 m²
Maximum area is 25 m²
Hope this helps
Given a term in a geometric sequence and the common ratio find the first five terms, the explicit formula, and the recursive formula. Given two terms in a geometric sequence find the 8th term and the recursive formula. Determine if the sequence is geometric. If it is, find the common ratio.
What does this mean buddy?
Answer:
(3x + 4)(x - 1)
Step-by-step explanation:
3x^2 + x - 4
use middle term break method
we need two number which gives 12 when multiplied and 1 when subtracted
3x^2 + (4 - 3)x - 4
3x^2 + 4x - 3x - 4
x(3x + 4) -1(3x + 4)
(3x + 4)(x - 1)
Answer:
1) 5/6
2) 7/10
3) 3 1/8
4) 3 2/7
5) 1 8/9
Step-by-step explanation:
