It would be none because the same would be the reciprocal which would be (-7, -8.75)
= 40(t^2 - 10t + 12.5) answer
Answer:
<u><em>−125a^(11)</em></u>
Step-by-step explanation:
<u><em>(−5a^(2)3a^(5) Then you solve</em></u>
<u><em>=−125a^(11)</em></u>
Answer:
yes
Step-by-step explanation:
1.2.3.4
Answer:
(5,6) , (5,-2)
Step-by-step explanation:
Let the required point be P(5,y).
Its distance from (2,2) is 5 units.
So,
+
= 25.
So,
+
= 25.
9 +
= 25.
= 16
Two cases are possible for now
case 1 : y-2 = 4 .
y = 6
required point will be (5,6)
case 2 : y - 2 = -4.
y = -2.
required point will be (5,-2).
Two points are possible : (5,6) , (5,-2).