Answer:
The minimum score required for admission is 21.9.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
A university plans to admit students whose scores are in the top 40%. What is the minimum score required for admission?
Top 40%, so at least 100-40 = 60th percentile. The 60th percentile is the value of X when Z has a pvalue of 0.6. So it is X when Z = 0.255. So
The minimum score required for admission is 21.9.
Id say B, y=-2/3+3
Hope this helps
Add all the chips to find the total amount.
7 + 9 + 3 + 6 = 25 chips
Since there are 6 blue chips (6/25), that's the probability of just getting once.
When you pick a blue chip and it doesn't get replaced, then that means there is one fewer blue chip and one fewer from the total amount.
5/24
Multiply both probabilities.
6/25 * 5/24 = 30/600
Simplify.
30/600 → 1/20
Therefore, the answer is B
Best of Luck!
Answer:
A. Tossing 5 coins and getting 4 heads
Step-by-step explanation:
Compound events may be described as events whose occurence has more than one possible outcome, that is the number of possible events is more than one. From the options given above, Rolling 3 on a die, this event has only one possible outcome, which is rolling 3 ; tossing a coin and getting tails also has one obe possible outcome. Drawing 10 diamonds from a deck also focuses on one event which is drwinh diamonds. However, tossing 5 coins and getting 4 heads involves that the 5th toss will be tail. This has more than one event and thus a compound event.