Answer:
Option (B)
Step-by-step explanation:
To calculate the distance between C2 and SW1 we will use the formula of distance between two points 
and 
.
d = 
Coordinates representing positions of C2 and SW1 are (2, 2) and (-6, -7) respectively.
By substituting these coordinates in the formula,
Distance between these points = 
= 
= 
units
Therefore, Option (B) will be the correct option.
Answer:
7a........they are similar because none of the sides are equal
6×ax+6×by =6ax+6by =3a+2b,6×bx-6×ay=3b-2a=6bx-3a+2b
We are given with
dimensions of wheelbarrow = 2ft x 3ft x 1.5 ft
dimensions of truck = 11 ft x 8 ft x 6 ft
The volume of the wheelbarrow is 2(3)(1.5) = 9 ft3
The volume of the truck is 11(8)(6) = 528 ft3
70% of this is
528 ft3 (0.7) = 369.6 ft3
Dividing this by the volume of the wheelbarrow
369.6 ft3 / 9 ft3 = 41.07
He would need to use the wheelbarrow 42 times.
First we have to calculate the half-life
half-life = elapsed time * log (2) / log (bgn amt / end amt)
half-life = 1 hour * 0.30102999566 / log (1 / .95)
half-life = 0.30102999566 / log (<span>
<span>
<span>
1.0526315789 )
</span>
</span>
</span>half-life = 0.30102999566 / 0.022276394692
half-life = <span>
<span>
<span>
13.5134073454 hours
</span>
</span>
</span>
Ending Amount = Beginning Amount / 2^n
Where "n" = number of half-lives
For 4 hours, "n" equals
4 / 13.5134073454
=<span>
<span>
<span>
0.2960023255
</span></span></span>Ending Amount = 500 grams / 2^.2960023255
Ending Amount = 500 grams /<span>
<span>
<span>
1.2277376629
</span>
</span>
</span>Ending Amount = <span>
<span>
<span>
407.2531250707 grams
Source:
http://www.1728.org/halflife.htm
</span></span></span>
