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3 years ago

How do I prove that (1+sinx)/cosx=cos(-x)/(1+sine(-x))

Mathematics

1 answer:

stira [4]3 years ago

5 0

$\dfrac{1+\sin x}{\cos x}=\dfrac{\cos (-x)}{1+\sin(-x)}\\
\dfrac{1+\sin x}{\cos x}=\dfrac{\cos x}{1-\sin x}\\
\cos^2 x=(1+\sin x)(1-\sin x)\\
\cos^2 x=1-\sin^2 x\\
\sin^2 x+\cos^2 x=1
$

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Vilka [71]

The difference between the functions give:

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<h3>How to find the difference between the functions?</h3>

For two functions f(x) and g(x), the difference is defined as:

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By looking at the given tables, we know that:

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goldenfox [79]

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3 years ago

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3 years ago

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see explanation

Step-by-step explanation:

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