Question

Suppose that 10 fair coins are tossed. Find the numbers of ways of obtaining exactly 1 heads. Round the answer to the nearest whole number

Answer 1

Answer: 10

Step-by-step explanation:

Given : Total number of coins tossed = 10

Possible outcomes to toss a coin = Head or tail

Number of possible outcomes = $2^{10}=1024$

Number of ways of obtaining exactly 1 heads = ${10}C_1=\dfrac{10!}{1!9!}$     [using combinations $^nC_r=\dfrac{n!}{r!(n-r)!}$ ]

=10

Hence, the numbers of ways of obtaining exactly 1 heads= 10