What is the value of b^2-4ac for the following equation?
1 answer:
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Answer:
Angle DCA = Angle CAB
Angle A + Angle B + Angle C = 180°
18 + 3x + 3x = 180
27°
Step-by-step explanation:
For 1:
Angle DCA = Angle CAB (Alternate angles are equal)
Angle DCA = 18°, Hence, CAB = 18°
2)
Angle A + Angle B + Angle C = 180° (sum of interior angles in a triangle)
3.)
Angle A = 18°
Angle B = 3x
Angle C = 3x
18° + 3x + 3x = 180°
4.)
18 + 3x + 3x = 180
18 + 6x = 180
6x = 180 - 18
6x = 162
x = 162 / 6
x = 27°
The answer is option c (-1,0)
Solving the equation you get that the zeros of this are approximately
x ≈ -2.8019
x ≈ -1.4450
x ≈ 0.24698
Then the function has three real roots, but none of them is within the range (-1,0)
Below is a graph of the function.
Solving the equation you get that the zeros of this are approximately
x ≈ -2.8019
x ≈ -1.4450
x ≈ 0.24698
Then the function has three real roots, but none of them is within the range (-1,0)
Below is a graph of the function.