What is the value of b^2-4ac for the following equation?

How does an outlier effect the median of a population?

neonofarm [45]

An outlier causes the median to move slightly towards the outlier.

5 0

3 years ago

Which ordered pair (a, b) is a solution to the given system of linear equations? -2a+3b=14

Stels [109]

Answer:

The solution of the system is the ordered pair (-13,-4)

Step-by-step explanation:

we have

$-2a+3b=14$ -----> equation A

$a-4b=3$ ----> equation B

Solve the system by elimination

Multiply by 2 both sides equation B

$2(a-4b)=2(3)$

$2a-8b=6$ ----> equation C

Adds equation A and equation C

$-2a+3b=14\\2a-8b=6\\-------\\3b-8b=14+6\\-5b=20\\b=-4$

<em>Find the value of a</em>

substitute the value of b in any equation (i take equation B)

$a-4(-4)=3$

$a+16=3$

$a=-13$

therefore

The solution of the system is the ordered pair (-13,-4)

6 0

4 years ago

Read 2 more answers

The monthly average temperature, T, for San Francisco is usually within 7.5 degrees and 56.5 degrees, inclusive. What is the mon

erica [24]

49 es la temperatura mensual

5 0

3 years ago

It says factor each expression 49x-28?

NARA [144]

Answer:

7(7x -4)

Step-by-step explanation:

49x-28

We can factor a 7 from each term

49x = 7*7x

28 = 7*4

7(7x -4)

3 0

4 years ago

Write an equation for a quadratic function that has x intercepts (-3, 0) and (5, 0)

Blizzard [7]

Answer:

One possible equation is $f(x) = (x + 3)\, (x - 5)$ , which is equivalent to $f(x) = x^{2} - 2\, x - 15$ .

Step-by-step explanation:

The factor theorem states that if $x = x_{0}$ (where $x_{0}$ is a constant) is a root of a function, $(x - x_{0})$ would be a factor of that function.

The question states that $(-3,\, 0)$ and $(5,\, 0)$ are $x$ -intercepts of this function. In other words, $x = -3$ and $x = 5$ would both set the value of this quadratic function to $0$ . Thus, $x = -3\!$ and $x = 5\!$ would be two roots of this function.

By the factor theorem, $(x - (-3))$ and $(x - 5)$ would be two factors of this function.

Because the function in this question is quadratic, $(x - (-3))$ and $(x - 5)$ would be the only two factors of this function. In other words, for some constant $a$ ( $a \ne 0$ ):

$f(x) = a\, (x - (-3))\, (x - 5)$ .

Simplify to obtain:

$f(x) = a\, (x + 3)\, (x - 5)$ .

Expand this expression to obtain:

$f(x) = a\, (x^{2} - 2\, x - 15)$ .

(Quadratic functions are polynomials of degree two. If this function has any factor other than $(x - (-3))$ and $(x - 5)$ , expanding the expression would give a polynomial of degree at least three- not quadratic.)

Every non-zero value of $a$ corresponds to a distinct quadratic function with $x$ -intercepts $(-3,\, 0)$ and $(5,\, 0)$ . For example, with $a = 1$ :

$f(x) = (x + 3)\, (x - 5)$ , or equivalently,

$f(x) = x^{2} - 2\, x - 15$ .

6 0

2 years ago