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Alborosie
3 years ago
15

Which of the following radical expressions simplifies to 6x^4y^3√2y?

Mathematics
1 answer:
Norma-Jean [14]3 years ago
6 0
The answer is J. Brainliest please :)
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What is the greatest common factor of 4k, 18k4, and 12?
Setler [38]

Answer:  The greatest common factor is 2.

Step-by-step explanation:  We are given to find the greatest common factor of the following expressions:

E_1=4k,~~E_2=18k^4,~~E_3=12.

<u>Greatest Common Factor:</u>  The GCF of two or more numbers (expressions)  is the greatest factor that divides all the numbers or expressions.

We have

E_1=4k=2\times 2\times k,\\\\E_2=18k^4=2\times 3\times 3\times k\times k\times k\times k,\\\\E_3=12=2\times 2\times 3.

Therefore, the greatest common factor will be

G.C.F.=2.

Thus, the required greatest common factor is 2.

6 0
3 years ago
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Licemer1 [7]

Answer:

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3 years ago
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SOMEONE PLEASE ANSWER ASAP THIS FOR BRAINLIEST!!!!
kirill115 [55]

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3 0
3 years ago
The dwarves of the Grey Mountains wish to conduct a survey of their pick-axes in order to construct a 99% confidence interval ab
Dmitry_Shevchenko [17]

Answer:

The minimum sample size needed is 125.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

For this problem, we have that:

\pi = 0.25

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

What minimum sample size would be necessary in order ensure a margin of error of 10 percentage points (or less) if they use the prior estimate that 25 percent of the pick-axes are in need of repair?

This minimum sample size is n.

n is found when M = 0.1

So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.1 = 2.575\sqrt{\frac{0.25*0.75}{n}}

0.1\sqrt{n} = 2.575{0.25*0.75}

\sqrt{n} = \frac{2.575{0.25*0.75}}{0.1}

(\sqrt{n})^{2} = (\frac{2.575{0.25*0.75}}{0.1})^{2}

n = 124.32

Rounding up

The minimum sample size needed is 125.

5 0
4 years ago
The base of a regular pyramid is a hexagon. The figure shows a regular hexagon with center C. An apothem is shown as a dashed se
tatuchka [14]
Answer: 294√3

Explanation:


1) The described hexagon has these featrues:
a) 6 congruent equilateral triangles whose side lengths measure 14
b) height of each triangle = apotema = a
c) the area of each triangle is base × a / 2 = 14 × a / 2 = 7a


2) a is one leg of a right triangle whose other leg is 14 / 2 = 7, and the hypotenuse is 14.

3) Then you can use Pythagorean theorem fo find a:

14² = 7² + a² ⇒ a² = 14² - 7² = 147 ⇒ a = √ 147 = 7√3

4) Therefore, the area of one triangle is: 14 × 7√3  / 2 = 49√3

5) And the area of the hexagon is 6 times that: 6 × 49√3 = 294√3
8 0
3 years ago
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