Answer:
Answer for the question:
To compute a19 mod N, the modular exponential algorithms that we studied would do 8 modular multiplications (5 squarings and 3 multiplications by a). What is the minimum number of modular multiplications needed to compute a19 mod N if you are free to use any sequence of modular multiplications.)
is given in the attachment.
Step-by-step explanation:
Answer: B. 264
Step-by-step explanation:
Formula to calculate the sample size 'n' , if the prior estimate of the population proportion (p) is available:
, where z = Critical z-value corresponds to the given confidence interval
E= margin of error
Let p be the population proportion of clear days.
As per given , we have
Prior sample size : n= 150
Number of clear days in that sample = 117
Prior estimate of the population proportion of clear days = 
E= 0.05
The critical z-value corresponding to 95% confidence interval = z*= 1.95 (By z-table)
Then, the required sample size will be :
Simplify ,
Hence, the sample size necessary to construct this interval =264
Thus the correct option is B. 264
Answer:
Step-by-step explanation:
A=1/2(r+2)
2A=f(r+2)
2A/f=r+2
2A/f-2=r
X = 24 so the value of x is 24
Answer: y=66
I hope it helps you!