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2 years ago

Graph the function f(x)=(1/3)^x+2-6

Mathematics

1 answer:

Hitman42 [59]2 years ago

3 0

I got this picture from photomath, hope it helps

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the answer is 69.3

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2 years ago

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AURORKA [14]

Answer:a

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2 years ago

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Veda solves the following system of linear equations by eliminations. What is the vale of x in the solution of the system of equ

kupik [55]

Answer:

x = -1, y = 1

Step-by-step explanation:

6 + 4x - 2y = 0 (1)

-3 - 7y = 10x (2)

From (1)

6 + 4x - 2y = 0 (1)

4x - 2y = -6 (3)

From (2)

-3 - 7y = 10x (2)

10x + 7y = -3 (4)

4x - 2y = -6 (3)

10x + 7y = -3 (4)

Using elimination method

Multiply (3) by 10 and (4) by 4 to eliminate x

40x - 20y = -60

40x + 28y = -12

28y - (-20y) = -12 - (-60)

28y + 20y = -12 + 60

48y = 48

y = 48/48

y = 1

Substitute y = 1 into (3)

4x - 2y = -6 (3)

4x - 2(1) = -6

4x - 2 = -6

4x = -6 + 2

4x = -4

x = -4/4

x = -1

x = -1, y = 1

The value of x in the equation is -1

4 0

2 years ago

The length of a rectangle is 6 more than twice the width. if the area is 40 cm^2, find the length and breadth of the rectangle

ra1l [238]

Answer: 3.217 & 12.434

Step-by-step explanation:

If we use w to represent the width, the length will be 6 more than 2 times w.

Hence, the length is $2w+6$ .

The area of a rectangle would be its length times its width, so let's make an equation to represent it's area.

$A=w(2w+6)$

We can also substitute 40 in for A as it's given in the question.

$40 = w(2w+6)$

Distributing w by multiplying it by both terms in the parentheses, we get

$40 = 2w^2+6w$

We can make the equation simpler by dividing both sides by 2.

$20 = w^2+3w$

Subtracting both sides by 20 will make the left-hand side 0.

$0=w^2+3w-20$

Now that we have put this quadratic equation into standard form (ax²+bx+c), we can find its solutions using the quadratic formula.

For reference, the quadratic formula is

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

In this case, a is 1, b is 3, and c is -20.

Substituting, we get

$w=\frac{-3\pm\sqrt{3^2-4(1)(-20)}}{2(1)}$

$w= \frac{-3\pm\sqrt{9+80}}{2}$

$w=\frac{-3+\sqrt{89}}{2}\hspace{0.1cm}or\hspace{0.1cm}\frac{-3-\sqrt{89}}{2}$

Since the second solution results in a negative number, it cannot be the length of w.

$w=\frac{-3+\sqrt{89}}{2}\approx3.217$

The width/breadth of the rectangle is 3.217 cm.

To calculate the length, let's substitute the width into the expression for the length:

$l=2(3.217)+6$

$l=12.434$

The length of this rectangle is 12.434 cm.

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1 year ago

In a certain Algebra 2 class of 29 students, 18 of them play basketball and 7 of them play baseball. There are 2 students who pl

Natasha2012 [34]

Answer:

24/.29

Step-by-step explanation:

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3 years ago

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