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Elena L [17]
3 years ago
7

Could someone please help me with this problem.

Mathematics
2 answers:
lana66690 [7]3 years ago
5 0
Z = 72
y = 106

hope it helps
lakkis [162]3 years ago
5 0
Please correct me if I'm wrong but I think y is 106 and z is 72
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Blizzard [7]
5:2
because you need to divide them by 8 to get to simplest form
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3 years ago
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If 5(3x-7)=20, then what is 6x-8 ?
Colt1911 [192]
First solve for x in the first equation. So you'll have to substitute,
5(3x-7)=20
15x-35=20
Then add 35 to both sides.
15x=55
Divide 55 by 15.
So x = 3.66...
Then plug in 3.7 for x in 6x-8
6(3.7)-8
Its approximately 14.2
3 0
3 years ago
For his phone service, Charlie pays a monthly fee of $ 18 , and he pays an additional $ 0.06 per minute of use. The least he has
schepotkina [342]

Answer:

Charlie has used his phone in a month for at least 1404 minutes

Step-by-step explanation:

In order to solve this problem, we must first determine what will our variable be and what it will represent.

Let's say our variable is x and it will represent the number of minutes Charlie has used his phone.

After we set our variable up, we can set our equation up. The problem states that Charlie will pay a monthly fee of $18 and additional $0.06 per minute of use. The $18 is what is called a fixed cost and the $0.06 is the variable cost, which will depend on our variable x (the number of minutes spent). Taking this into account we can build an inequality that will represent the amount of money spent in a month, which will look like this:

18+0.06x\geq 102.24

so now we can solve that inequality for x, we can start by subtracting 18 from both sides, so we get.

18+0.06x-18\geq 102.24-18\\\\0.06x\geq 84.24

Next, we can divide both sides of the inequality by 0.06 so we get:

0.06x/0.06\geq 84.24/0.06\\\\x\geq 1404

so that's where the answer came from. Charly has used an amount of at least 1404 minutes

7 0
3 years ago
Will is twice as old as Jill. Three years ago, Jill's age was two fifths of Will's age then. How old is each now?
dimulka [17.4K]
"Will is twice as old as Jill."

                       Jill's age . . . . .   J
                       Will's age . . . . 2J .

"Three years ago . . .

                       Jill's age then . . . . .   J - 3
                       Will's age then . . . . 2J - 3

". . . Jill's age then was 2/5 of Will's age then."

                                         J - 3  =  (2/5) (2J - 3)
Multiply
each side by  5 :          5J - 15  =  2 (2J - 3)

Divide
each side by  2 :          2.5 J - 7.5  =  2J - 3 

Subtract  2J
from each side:            0.5 J - 7.5  =      -3

Add  7.5
to each side:                0.5 J           =     4.5

Multiply
each side by  2 :                J            =       9

Jill is  9  y.o. now.
Will is 18 y.o. now.

4 0
3 years ago
7x2+3[81-(4x6)]<br> Simplify
4vir4ik [10]
P E M D A S

Pren
Equ
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Add 
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5 0
3 years ago
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