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likoan [24]
3 years ago
14

How do you factor 3u^3-4u^2-9u+12 ? Can someone please help?

Mathematics
1 answer:
Juliette [100K]3 years ago
5 0
3u³ - 4u² - 9u + 12
u²(3u) - u²(4) - 3(3u) + 3(4)
u²(3u - 4) - 3(3u - 4)
(u² - 3)(3u - 4)
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Name the symbol used in 2nd generation language

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**IF ANYONE CAN DO ALL OF THESE QUESTIONS CORRECTLY AND FAST, YOU WILK BE MARKED BRAINLIEST!!**What is the measure of arc BC?
bixtya [17]

I think the answer is BC= (bc + de)/2

7 0
3 years ago
Very confused with this
OlgaM077 [116]

Answer:

∠ D = 28°

Step-by-step explanation:

The external angle of a triangle is equal to the sum of the 2 opposite interior angles.

∠ EBC is an exterior angle of Δ ABE, thus

∠ EBC = 90° + 34° = 124°

BD bisects ∠ EBC, so

∠ EBD = 124° ÷ 2 = 62° , then

∠ D = 180° - (90 + 62)° = 180° - 152° = 28° ( angle sum of triangle )

4 0
3 years ago
C(1, 6) ; y=4x+1<br> Put answer in slope intercept form
alina1380 [7]

Answer:

slope intercept form is y=mx+b

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y=4x+6

4 0
3 years ago
(ASAP PICTURE ADDED) What is the simplified form of the following expression?
bonufazy [111]

Answer:

option c is correct.

Step-by-step explanation:

7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{16x}\right)-3\left(\sqrt[3]{8x}\right)

WE need to simplify this equation.

Solve the parenthesis of each term.

=7\left\sqrt[3]{2x}\right-3\left\sqrt[3]{16x}\right-3\left\sqrt[3]{8x}\right

Now, We will find factors of the terms inside the square root

factors of 2: 2

factors of 16 : 2x2x2x2

factors of 8: 2x2x2

Putting these values in our equation:=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2X2 x}\right)-3\left(\sqrt[3]{2X2X2 x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3*2\left(\sqrt[3] {2 x}\right)-3*2\left(\sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)

Adding like terms we get:

=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right\\=(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)\\

(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)\\can\,\,be \,\, written\,\, as\,\,\\(\sqrt[3] {2x})-6\left(\sqrt[3]{x}\right)

So, option c is correct

5 0
3 years ago
Read 2 more answers
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