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likoan [24]
4 years ago
14

How do you factor 3u^3-4u^2-9u+12 ? Can someone please help?

Mathematics
1 answer:
Juliette [100K]4 years ago
5 0
3u³ - 4u² - 9u + 12
u²(3u) - u²(4) - 3(3u) + 3(4)
u²(3u - 4) - 3(3u - 4)
(u² - 3)(3u - 4)
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FREE BRAINLIEST IF YOU ANSWER CORRECTLY & FIRST!!!! ASAP PLEASE!!!
Sati [7]

The surface area of the prism based on the net provided will be 184 square meters.

<h3>What is the surface area of a triangular prism?</h3>

Let h be the height and b be the base of the triangle.

Let L₁, L₂, and L₃ be the length and W be the width of the rectangle.

Then the surface area of the triangular prism will be

Surface area = 2 Area of triangle + 3 Area of rectangle

Surface area = h x b + (L₁ + L₂ + L₃) x W

From the figure, the length of the rectangles will be 5 m, 6 m, and 5m,  and the width is 10 m.

From the figure, the height is 4 m and the base is 6 m of the triangle. Then we have

Surface area = 4 x 6 + (6 + 5 + 5) x 10

Surface area = 24 + 16 x 10

Surface area = 24 + 160

Surface area = 184 square m

The surface area of the prism based on the net provided will be 184 square meters.

More about the surface area of a triangular prism link is given below.

brainly.com/question/16765719

#SPJ5

3 0
2 years ago
Read 2 more answers
Four rats are selected at random from a cage of 5 male (M) and 6 female (F) rats. If the random variable Y is concerned with the
Ludmilka [50]

Using the hypergeometric distribution, it is found that the distribution is:

P(X = 0) = 0.0152

P(X = 1) = 0.1818

P(X = 2) = 0.4545

P(X = 3) = 0.3030

P(X = 4) = 0.0455

Hence:

A) There is a 0.0455 = 4.55% probability that all selected rats are female.

B) There is a 0.1818 = 18.18% probability that only one of the selected rats is female.

C) There is a 0.803 = 80.3% probability that at least two of the selected rats is female.

D) The mean of the probability distribution is of 2.18.

E) The standard deviation of the probability distribution is of 0.833.

The rats are chosen without replacement, hence the <em>hypergeometric distribution</em> is used to solve this question.

<h3>What is the hypergeometric distribution formula?</h3>

The formula is:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • N is the size of the population.
  • n is the size of the sample.
  • k is the total number of desired outcomes.

In this problem:

  • There is a total of 11 rats, hence N = 11.
  • 6 of the rats are female, hence k = 6.
  • 4 rats are taken, hence n = 4.

The distribution is the probability of each outcome, hence:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

P(X = 0) = h(0,11,4,6) = \frac{C_{6,0}C_{5,4}}{C_{11,4}} = 0.0152

P(X = 1) = h(1,11,4,6) = \frac{C_{6,1}C_{5,3}}{C_{11,4}} = 0.1818

P(X = 2) = h(2,11,4,6) = \frac{C_{6,2}C_{5,2}}{C_{11,4}} = 0.4545

P(X = 3) = h(3,11,4,6) = \frac{C_{6,3}C_{5,1}}{C_{11,4}} = 0.3030

P(X = 4) = h(4,11,4,6) = \frac{C_{6,4}C_{5,0}}{C_{11,4}} = 0.0455

Item a:

P(X = 4) = 0.0455, hence:

There is a 0.0455 = 4.55% probability that all selected rats are female.

Item b:

P(X = 1) = 0.1818, hence:

There is a 0.1818 = 18.18% probability that only one of the selected rats is female.

Item c:

P(X \geq 2) = P(X = 2) + P(X = 3) + P(X = 4) = 0.4545 + 0.3030 + 0.0455 = 0.803

There is a 0.803 = 80.3% probability that at least two of the selected rats is female.

Item d:

The mean of the hypergeometric distribution is:

\mu = \frac{nk}{N}

Hence:

\mu = \frac{4(6)}{11} = 2.18

The mean of the probability distribution is of 2.18.

Item e:

The standard deviation of the hypergeometric distribution is:

\sigma = \sqrt{\frac{nk(N-k)(N-n)}{N^2(N-1)}}

Hence:

\sigma = \sqrt{\frac{4(6)(11-6)(11-4)}{11^2(11-1)}} = 0.833

The standard deviation of the probability distribution is of 0.833.

More can be learned about the hypergeometric distribution at brainly.com/question/24826394

5 0
2 years ago
Finish solving the system of equations.
sergejj [24]

Answers:  x = 1 and y = -1

Explanation:

Start where your teacher left off, which is -3y = 3.

We solve for y by dividing both sides by -3

That turns -3y = 3 into y = -1

Then we use this y value to find x

x - 5y = 6

x - 5(-1) = 6

x + 5 = 6

x = 6-5

x = 1

The solution is (x,y) = (1, -1)

4 0
3 years ago
Read 2 more answers
​ A loggerhead sea turtle decided to swim to grab some lunch! She swam 4 miles west and 3 miles south until she stopped and foun
Alja [10]

Answer:

Down below.

Step-by-step explanation:

Use Pythagorean’s Theron

9 + 16 = c squared

25 = c squared

c = 5

6 0
3 years ago
Whats 3 x 5<br> pls i give brainlieistsd
storchak [24]

Answer:

the answer is 15 hdkdiemidd

3 0
3 years ago
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