How do you factor 3u^3-4u^2-9u+12 ? Can someone please help?

1 answer:

5 0

3u³ - 4u² - 9u + 12
u²(3u) - u²(4) - 3(3u) + 3(4)
u²(3u - 4) - 3(3u - 4)
(u² - 3)(3u - 4)

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