Answer:
$38.69
Step-by-step explanation:
To find the regular price, create a proportion.

To solve for the regular price x, cross multiply the numerator and denominator of each fraction.
32.89*(100) = x(85)
3289=85x
38.69 = x
Answer:
See the attachment
Step-by-step explanation:
It is convenient to use a spreadsheet or graphing calculator for this.
Answer:
angle is 45° which is constant
Step-by-step explanation:
We use formula for two vectors <u>a </u>and <u>b</u> to calculate angle θ between them by formula
cos θ = <u>a .</u> <u>b</u> / magnitude of <u>a </u> × magnitude of <u>b</u>
<u>Please see the attached file</u>
Answer:
option C

Step-by-step explanation:
we have

using a graphing tool
see the attached figure N
The range is the interval--------> (-∞,8]

case A) 
using a graphing tool
The range is the interval--------> [-8,∞)

case B) 
using a graphing tool
The range is the interval--------> [8,∞)

case C) 
using a graphing tool
The range is the interval--------> (-∞,8]

case D) 
using a graphing tool
The range is the interval--------> (-∞,-8]

If a ratio of skiers and snumboarders is 1:2, and if there are 1250 snowboarders more than skiers, it means that is that there 2500 snowboarders and 1250 skiers.
How to check it? 2500 is 1250 more than 1250 and the ratio is still 1:2 (there are two times more snowboarders than skiers). Both conditions are fulfiled, so it's correct.