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IrinaVladis [17]

3 years ago

14

Plz help me on this question

1 answer:

Deffense [45]3 years ago

4 0

Let number $c=\sqrt{45}.$

Square this number:

$c^2=45.$

Since

$36$

you can state that

$\sqrt{36}$

Also $\sqrt{45}\approx 6.708$ and $6.5$ , then point C is the best approximation of $\sqrt{45}.$

Answer: option C.

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The process that produces Sonora Bars (a type of candy) is intended to produce bars with a mean weight of 56 gm. A random sample

oksano4ka [1.4K]

Answer:

$t=\frac{55.82-56}{\frac{0.77}{\sqrt{49}}}=-1.636$

Step-by-step explanation:

Data given and notation

$\bar X=55.82$ represent the sample mean

$s=0.77$ represent the standard deviation for the sample

$n=49$ sample size

$\mu_o =56$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

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$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the mean is less than 56, the system of hypothesis would be:

Null hypothesis: $\mu \geq 56$

Alternative hypothesis: $\mu < 56$

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{55.82-56}{\frac{0.77}{\sqrt{49}}}=-1.636$

4 0

4 years ago

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musickatia [10]

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60-30=30
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3 years ago

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So u want 3/4 cup x 3 and 1/2

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3 years ago

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