Answer:
Check the explanation
Step-by-step explanation:
(a)Let p be the smallest prime divisor of (n!)^2+1 if p<=n then p|n! Hence p can not divide (n!)^2+1. Hence p>n
(b) (n!)^2=-1 mod p now by format theorem (n!)^(p-1)= 1 mod p ( as p doesn't divide (n!)^2)
Hence (-1)^(p-1)/2= 1 mod p hence [ as p-1/2 is an integer] and hence( p-1)/2 is even number hence p is of the form 4k+1
(C) now let p be the largest prime of the form 4k+1 consider x= (p!)^2+1 . Let q be the smallest prime dividing x . By the previous exercises q> p and q is also of the form 4k+1 hence contradiction. Hence P_1 is infinite
Answer:
125 feet below sea level or -125
Step-by-step explanation:
Whats the problem that you need help with
Answer:
an expression of more than two algebraic terms, especially the sum of several terms that contain different powers of the same variable(s).
Answer:
we know that
The volume of the prism is equal to
V=L*W*H
where
L is the length side of the base of the prism
W is the width side of the base of the prism
H is the height of the prism
In this problem we have
L=\frac{d-2}{3d-9}=\frac{d-2}{3(d-3)}
W=\frac{4}{d-4}
H=\frac{2d-6}{2d-4}=\frac{2(d-3)}{2(d-2)}=\frac{(d-3)}{(d-2)}
Substitute the values in the formula
V=\frac{d-2}{3(d-3)}*\frac{4}{d-4}*\frac{(d-3)}{(d-2)}=\frac{4}{3(d-4)}=\frac{4}{3d-12}
therefore
the answer is the option
4/3d-12
Step-by-step explanation:
