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sergiy2304 [10]
3 years ago
7

Srurface area 1m 2m 1m

Mathematics
2 answers:
yuradex [85]3 years ago
6 0

Answer: it would be 2

Step-by-step explanation:

babymother [125]3 years ago
3 0

Answer:4

Step-by-step explanation: 1x2x1x2

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The area of a circular wave expands across a still pond such that its radius increases by 14 cm each second. Write a formula for
lara31 [8.8K]

Answer:

A = π(14t)²

Step-by-step explanation:

The radius is increasing at the rate of 14 cm per second.

We need to find the formula for the area A of the circle as the function of time t.

Initial area of the circle,

A = πr², where r is the radius of the circle

Area as a function of t will be :

A = π(14t)²

Here, 14t is the radius of the wave.

4 0
2 years ago
Li deposited $17,500 into a bank account that earned simple interest each year. After 2 years, he had earned $2975 in interest.
Keith_Richards [23]

Answer:

The annual interest rate was $1487.50

Step-by-step explanation:

All you do is 2975 divided by2=1487.50

4 0
3 years ago
Prove each statement that is true and find a counterexample for each statement that is false. Assume all sets are subsets of a un
tekilochka [14]

Answer with Step-by-step explanation:

We are given that A, B and C are subsets of universal set U.

We have to prove that

A\cap (B-C)=(A\cap B)-(A\cap C)

Proof:

Let x\in A\cap (B-C)

Then x\in A and x\in(B-C)

When x\in ( B-C)then x\in B but x\notin C

Therefore, x\in( A\cap B) but x\notin (A\cap C)

Hence, it is true.

Conversely , Let x\in(A\cap B) but x\notin(A\cap C)

Then x\in A and x\in B

When x\notin ( A\cap C) then x\notin C

Therefor,x\in A\cap (B-C)

Hence, the statement is true.

5 0
3 years ago
3) Write the operation used to obtain the types of solutions.
Alex Ar [27]

Answer:

the Sum

hope this helps

5 0
3 years ago
Read 2 more answers
The Office of Student Services at a large western state university maintains information on the study habits of its full-time st
Vera_Pavlovna [14]

Answer:

0.8254 = 82.54% probability that the mean of this sample is between 19.25 hours and 21.0 hours

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 20 hours, standard deviation of 6:

This means that \mu = 20, \sigma = 6

Sample of 150:

This means that n = 150, s = \frac{6}{\sqrt{150}}

What is the probability that the mean of this sample is between 19.25 hours and 21.0 hours?

This is the p-value of Z when X = 21 subtracted by the p-value of Z when X = 19.5. So

X = 21

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{21 - 20}{\frac{6}{\sqrt{150}}}

Z = 2.04

Z = 2.04 has a p-value of 0.9793

X = 19.5

Z = \frac{X - \mu}{s}

Z = \frac{19.5 - 20}{\frac{6}{\sqrt{150}}}

Z = -1.02

Z = -1.02 has a p-value of 0.1539

0.9793 - 0.1539 = 0.8254

0.8254 = 82.54% probability that the mean of this sample is between 19.25 hours and 21.0 hours

3 0
3 years ago
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