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olga_2 [115]
3 years ago
14

6 - 1 * 16 + 21 ÷ 3 Please help !!

Mathematics
1 answer:
Airida [17]3 years ago
3 0

Answer:

-3

Explanation:

6 - 1 · 16 + 21 ÷ 3

21 ÷ 3 = 7

6 - 1 · 16 + 7

1 · 16 = 16

6 - 16 + 7

= -3

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X &lt; 36 and x &gt; -36<br>x &lt; 36 or x&gt;-36<br>x&lt; 36 or x &gt; 0<br>x &lt; 36 and x &gt; 0​
hjlf

Answer:

D,x < 36 and x > 0, negative number cannot be in sq.root

3 0
3 years ago
-3x-4=2x+5 ayuda es para hoy
lozanna [386]

Answer:

-9/5 which is equal to -1.8

Step-by-step explanation:

primero agregue 4 al lado derecho. esto cancelaría el 4 en el lado izquierdo. Luego reste 2 al lado izquierdo. esto cancelará el 2 en el lado derecho. obtendrías -9/5 que en forma simple es igual a -1.8

4 0
3 years ago
Abby, Benji, and Caitlin are training for a race. Last week, Abby ran 6One-half miles and Benji ran 8 miles. They ran a total of
vichka [17]

Answer:

C and D

Step-by-step explanation:

This is a comparision  problem. (C)

The totla bar represents 30.8 miles. (D)

Caitlin ran 16.3 miles.

Hope this helps!

6 0
3 years ago
Read 2 more answers
Which two numbers doesStartRoot 128 EndRoot lie between on a number line? 11. 0 and 11. 1 11. 2 and 11. 3 11. 3 and 11. 4 11. 4
Alex73 [517]

A number line is a representation of a graded straight line. The number √128  will lie between 11.3 and 11.4.

<h3>What is a number line?</h3>

A number line is a representation of a graded straight line that serves as an abstraction for real numbers, which are represented by the letter R. A real number is considered to correspond to every point on a number line, and a point to every real number.

In order to know the location of the √128, we need to write the number  √128 in decimal form, therefore, the value of √128 can be written as,

\sqrt{128} = 11.3137 \approx 11.31

Now, on the number line if we plot √128 we will see that it will lie between 11.3 and 11.4, as shown below.

Hence, the number √128  will lie between 11.3 and 11.4.

Learn more about Number Line:

brainly.com/question/557284

7 0
2 years ago
Find the area of obtuse triangle ABC when A=41 degrees, a=18cm, and b=22cm.
solniwko [45]

Answer:

36 cm²

Step-by-step explanation:

  • cos A=  (`sqrt(b)` + `sqrt(c)` - `sqrt(a)`)/(2bc)

⇒c ≈ 5 cm

Sabc= (1/2)bcsin A ≈ 36 cm²

5 0
3 years ago
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