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Hunter-Best [27]
3 years ago
11

Help answer question about triangles!

Mathematics
2 answers:
Anna11 [10]3 years ago
4 0

yes they are similiar is sam shape diffrent siz

Sauron [17]3 years ago
4 0

Yes they are similar due to the AA similarity theorem and the SSS similarity theorem. The AA stands for "angle angle". We have a pair of angles that are congruent which allows us to conclude that the triangles are similar. Check out the attached image "Figure 1" to see the angles in question. Note the color coding.

The SSS similarity theorem comes into play when we take the ratios of the corresponding sides. So,

20/5 = 4

48/12 = 4

52/13 = 4

each division results in 4; each side of the larger triangle is 4 times larger than the smaller corresponding side. Check out Figure 2 to see how the sides pair up.

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Use the information frompart a to write an equation representing the number of colories burned each minute while bowling. Let m
Fofino [41]

Answer:

To find the number of calories burned:

Find the Metabolic Equivalent of Task (MET) value of the task.

Calculate the number of calories burned per minute. (MET x body weight in kg x 3.5) / 200.

Multiply the calories burned per minute by the number of minutes of activity.

Now, as per the question, weight is 125 pounds (lb), we will convert the weight in kilogram (kg) which is 1 lb = 0.453 kg, it means 125 lb = 56.7

Now we have to find the MET,

A metabolic equivalent (MET) value is a measurement of the energy cost of a specific physical activity for a specific period of time.

For example. A MET of 1 would be roughly equivalent to a person's energy expenditure from sitting still in a room temperature and not actively digesting food.

As per the Calorie guide value of MET for bowling is 3.9

Now the overall formula is

Calorie Burn (x) = ((MET * body weight in kg * 3.5) / 200) * (Number of minutes) m

x = ((3.9*56.7*3.5)/200) * m

Finally, x = 3.87 m represents the number of calorie burned (x) while bowling m minutes.

8 0
2 years ago
<img src="https://tex.z-dn.net/?f=6x%5E2%20%3D%20726" id="TexFormula1" title="6x^2 = 726" alt="6x^2 = 726" align="absmiddle" cla
vova2212 [387]

Answer:

x=11\\

Step-by-step explanation:

6x^2=726 First, you need to divide everything by 6.

x^2=121Then you put everything in a radical to get this:

x=11

3 0
3 years ago
Read 2 more answers
Someone please help ASAP!!!!
IrinaVladis [17]
Steps:

A=bh/2

A= (18ft)(6ft)
_______
2
A = 108
____
2
A= 54ft^2
4 0
3 years ago
8x = 7x + 3<br><br> Would I combine the 8x and the 7x at all in this equation?
Kryger [21]
Yes...thats what u want to do. you want to get the x terms on one side and everything else on the other side.

8x = 7x + 3....so we will subtract 7x from both sides
8x - 7x = 7x - 7x + 3....simplify
1x, or just x = 3 (because ur 7x's cancelled each other out)

so ur answer is : x = 3

and u can check ur answer by subbing it back into the original equation.
8x = 7x + 3
8(3) = 7(3) + 3
24 = 21 + 3
24 = 24 (correct)
3 0
3 years ago
Read 2 more answers
How do you do this problem? I need to know how you found the answer.
Alexxandr [17]

to get the equation of a line, we simply need two points, say for the Red one ... notice in the graph the lines passes through (0,2) and (-1,6), so let's use those


\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{6}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-2}{-1-0}\implies \cfrac{4}{-1}\implies -4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=-4(x-0) \\\\\\ y-2=-4x\implies \blacktriangleright y=-4x+2 \blacktriangleleft


now, for the Blue one, say let's use hmmm it passes through (0,2) and (1.6)


\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{6}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-2}{1-0}\implies \cfrac{4}{1}\implies 4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=4(x-0) \\\\\\ y-2=4x\implies \blacktriangleright y=4x+2 \blacktriangleleft

3 0
3 years ago
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