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3 years ago

Calculate the area of the rectangle with a base of 15 inches and and an altitude of 7 inches

Mathematics

1 answer:

TiliK225 [7]3 years ago

4 0

Answer:

Step-by-step explanation:

it hs explanasion

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Radda [10]

I don't know what this is supposed to mean, but thanks for the free points! ;)

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3 years ago

NEED ASAP<br><br> 1. Find the distance between (3√3, √11) and (−5√3, 5√11)

VLD [36.1K]

Answer: $\sqrt20$

Step-by-step explanation

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2 years ago

Which expression is not equivalent to 8+(n-4)

MrRa [10]

Where's your options? give the full info please!

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2 years ago

Find each measurement indicated. Round your answers to the nearest tenth.

Crazy boy [7]

Answer:

Step-by-step explanation:

Find AB using the Law of Sine:

$\frac{AB}{sin(C)} = \frac{AC}{sin(B)}$

Thus:

$\frac{AB}{sin(40)} = \frac{47}{sin(103)}$

Multiply both sides by sin(40)

$\frac{AB}{sin(40)}*sin(40) = \frac{47}{sin(103)}*sin(40)$

$AB = \frac{47*Sin(40)}{sin(103)}$

AB = 31.0056916 ≈ 31.0 cm (nearest tenth)

6 0

3 years ago

Find the six trigonometric function values for angle ∅ where its adjacent side is -9 and its hypotenuse is 41. (Theta is located

arsen [322]

Check the picture below.

$\bf \textit{using the pythagorean theorem}
\\\\
c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\sqrt{41^2-(-9)^2}=b\implies \sqrt{1681-81}=b\\\\\\ \sqrt{1600}=b\implies 40=b\\\\
-------------------------------$

$\bf sin(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{hypotenuse}{41}}\qquad~~ cos(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{hypotenuse}{41}}\qquad~~ tan(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{adjacent}{-9}}
\\\\\\
csc(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{opposite}{40}}\qquad ~~sec(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{adjacent}{-9}}\qquad ~~cot(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{opposite}{40}}$

3 0

3 years ago