Cos(35) = x/6
or 6 * cos(35) = x
Answer:
5x + 2y = 12
Step-by-step explanation:
Direction factor = (2, 1) - (0, 6) = (2, -5)
So, normal factor = (5, 2)
Line: 5x + 2y = k
(0, 6) -> L: 0 + 12 = 12 = k
L: 5x + 2y = 12
The simplified form for (3x² + 2y² - 5x + y) + (2x² - 2xy - 2y² -5x + 3y) is (5x² + 0y² - 10x + 4y - 2xy).
<h3>A quadratic equation is what?</h3>
At least one squared term must be present because a quadratic is a second-degree polynomial equation. It is also known as quadratic equations. The answers to the issue are the values of the x that satisfy the quadratic equation. These solutions are called the roots or zeros of the quadratic equations. The solutions to the given equation are any polynomial's roots. A polynomial equation with a maximum degree of two is known as a quadratic equation, or simply quadratics.
<h3>How is an equation made simpler?</h3>
The equation can be made simpler by adding up all of the coefficients for the specified correspondent term through constructive addition or subtraction of terms, as suggested in the question.
Given, the equation is (3x² + 2y² - 5x + y) + (2x² - 2xy - 2y² -5x + 3y)
Removing brackets and the adding we get,
3x² + 2x² + 2y² - 2y² + (- 5x) + (- 5x) + y + 3y + (- 2xy) = (5x² + 0y² - 10x + 4y - 2xy)
To learn more about quadratic equations, tap on the link below:
brainly.com/question/1214333
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Answer:
C=10
Step-by-step explanation:
To solve this problem, first, you have to isolate it on one side of the equation. Remember, isolate c on one side of the equation.
3/2c+23-23=38-23 (subtract 23 from both sides.)
38-23 (solve.)
38-23=15
3/2c=15
2*3/2c=15*2 (multiply 2 from both sides.)
15*2 (solve.)
15*2=30
3c=30
3c/3=30/3 (divide by 3 from both sides.)
30/3 (solve.)
30/3=10
c=10
