Find the sum of deviation of all observations of the data 5, 8, 10, 15, 22 from their mean.

Mathematics

1 answer:

ivann1987 [24]2 years ago

3 0

Answer:

the sum of deviation of all observations of the data 5, 8, 10, 15, 22 from their mean. =26

Step-by-step explanation:

Mean=sum of observation/ No. of observation

={5+8+ 10+ 15 + 22}/5

=60/5=12

Sum of deviations

= |5- 12| + |8 – 12| + |10- 12| + |15- 12| + |22-12|

= 7+4+2+ 3+ 10

= 26

You might be interested in

Solve 2csc^2x-2cscx-1=0 <br> for 0° ≤ x ≤ 360°

umka21 [38]

Answer:

Step-by-step explanation:

2 csc²x-2 csc x-1=0

$\frac{2}{sin^2x} -\frac{2}{sin x} -1=0\\multiply~by~sin^2x\\2-2sin~x-sin^2x=0\\sin^2x+2sinx-2=0\\sin ~x=\frac{-2 \pm\sqrt{2^2-4*1*(-2)} }{2*1} \\=\frac{-2 \pm\sqrt{4+8} }{2} \\=\frac{-2 \pm\sqrt{4*3} }{2} \\=\frac{-2 \pm2\sqrt{3} }{2} \\=-1\pm\sqrt{3} \\|sin~x| \le ~1\\so~sin~x=-1+\sqrt{3} \\sin~x=\sqrt{3} -1\\x=sin^{-1}(\sqrt{3} -1) \approx 47.06^\circ,180-47.06\\or~x=47.06^\circ,132.94^\circ$