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charle [14.2K]
3 years ago
15

Mac's age is 3 years less than twice Joe's age. The sum of their ages is 30. Find their ages.

Mathematics
1 answer:
k0ka [10]3 years ago
4 0

Answer:

Mac is 19 years old, Joe is 11 years old

Step-by-step explanation:

2J - 3 = M

J + M = 30

M = 30 - J

2J - 3 = 30 - J

3J = 33

J = 11

M = 30 - 11

M = 19

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Step-by-step explanation:

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5 0
3 years ago
Lines 3x-2y+7=0 and 6x+ay-18=0 is perpendicular. What is the value of a?
BlackZzzverrR [31]

Answer:

\boxed{\sf a = 9 }

Step-by-step explanation:

Two lines are given to us which are perpendicular to each other and we need to find out the value of a . The given equations are ,

\sf\longrightarrow 3x - 2y +7=0

\sf\longrightarrow 6x +ay -18 = 0

Step 1 : <u>Conver</u><u>t</u><u> </u><u>the </u><u>equations</u><u> in</u><u> </u><u>slope</u><u> intercept</u><u> form</u><u> </u><u>of</u><u> the</u><u> line</u><u> </u><u>.</u>

\sf\longrightarrow y = \dfrac{3x}{2} +\dfrac{ 7 }{2}

and ,

\sf\longrightarrow y = -\dfrac{6x }{a}+\dfrac{18}{a}

Step 2: <u>Find </u><u>the</u><u> </u><u>slope</u><u> of</u><u> the</u><u> </u><u>lines </u><u>:</u><u>-</u>

Now we know that the product of slope of two perpendicular lines is -1. Therefore , from Slope Intercept Form of the line we can say that the slope of first line is ,

\sf\longrightarrow Slope_1 = \dfrac{3}{2}

And the slope of the second line is ,

\sf\longrightarrow Slope_2 =\dfrac{-6}{a}

Step 3: <u>Multiply</u><u> </u><u>the </u><u>slopes </u><u>:</u><u>-</u><u> </u>

\sf\longrightarrow \dfrac{3}{2}\times \dfrac{-6}{a}= -1

Multiply ,

\sf\longrightarrow \dfrac{-9}{a}= -1

Multiply both sides by a ,

\sf\longrightarrow (-1)a = -9

Divide both sides by -1 ,

\sf\longrightarrow \boxed{\blue{\sf a = 9 }}

<u>Hence </u><u>the</u><u> </u><u>value</u><u> of</u><u> a</u><u> </u><u>is </u><u>9</u><u> </u><u>.</u>

8 0
3 years ago
Helppp can someone solve this please
Norma-Jean [14]

Answer:

\displaystyle x=-15

Step-by-step explanation:

<u>Solution Of A System Of Equations </u>

A system of linear equations is given as

\displaystyle \left\{\begin{matrix}ax+by=c\\ dx+ey=f\end{matrix}\right.

There are many methods to solve them. We will use the method of reduction

The given system is

\displaystyle \left\{\begin{matrix}2x+3y=45\\ x+y=10\end{matrix}\right.

Multiplying the second equation by -3

\displaystyle \left\{\begin{matrix}2x+3y=45\\ -3x-3y=-30\end{matrix}\right.

Adding the resulting equations

\displaystyle -x=15

\displaystyle x=-15

5 0
3 years ago
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