Can't see the table but direct variation is: y = kx
So if the output is some constant multiple which could be positive, negative or fraction then yes it is direct variation. So just divide a couple y/x = k to see what you get.
Answer:
y = (4x - 9) / 5 or y = 4/5x - 9/5
Step-by-step explanation:
Solving for y
4x - 5y = 9
-5y = -4x + 9
5y = 4x - 9
y = (4x - 9) / 5 or y = 4/5x - 9/5
Answer:
There are 0.005 hundreds in 5/10.
Step-by-step explanation:
Claire drew model of 5/10
We want to know how many hundreds are in 5/10.
Let us use an obvious example.
There are three 2's in 6 right?
Suppose we didn't know this, and we are told to find how many 2's are in 6, we get this by representing this in an algebraic expression as:
There are x 2's in 6. This can be written as
2x = 6
Solving for x, by dividing both sides by 2, we have the number of 2's that are in 6.
x = 6/2 = 3.
Now, to our work
We want to find how many hundreds are in 5/10. We solve the equation
100x = 5/10
x = 5/1000 = 0.005
There are 0.005 hundreds in 5/10.
