DONT look at that photo. You have no idea what's in that link!
The answer is d) 6 batteries
Let f(x) = x² + 6x²-x+ 5 then ,
number to be added be P
then,
f(x) = x² + 6x²-x+ 5 +P
According to the qn,
(x+3) is exactly divisible by zero then,
R=0
comparing .. we get a= -3
now by remainder theorm
R=f(a)
0=f(-3)
0=(-3)² + 6(-3)²-(-3)+ 5 + P
0= 9 + 54 + 3 + 5 + P
-71=P
therefore, -71 should be added.
Hope you understand
Times what by 20% ? If you can ask me the full question i would love to help!
Y = x^2 - 16x + 17
-16/2 = (-8)
(-8)^2 = 64
Add 64 and subtract 64
y = x^2 - 16x + 64 + 17 - 64
y = (x - 8)^2 - 47
