All categories

3 years ago

Find the volume of a cone-shaped water cup with diameter 2.6 inches and height 2.6 inches.

Mathematics

1 answer:

UkoKoshka [18]3 years ago

5 0

Answer:

4.601 cubic inches.

Step-by-step explanation:

The volume of a cone is 1/3*pi*r^2*h, where r=d/2.

Using this, 1/3*pi*(2.6/2)^2*2.6=4.601 cubic inches.

You might be interested in

Is it possible to form a triangle with the given side lengths? 15 yd,16yd,30yd

lukranit [14]

<u>Answer:</u>

<u>Explanation:</u>

15 < 16+30

16 < 15+30

30 < 16+15

4 0

3 years ago

Read 2 more answers

Use the figure below to find the values of x and y

irinina [24]

Step-by-step explanation:

hey.. everyone please

Vmwaajtexf

come

3 0

2 years ago

Read 2 more answers

find the volume of the solid formed by revolving the region bounded by the graphs of y = 4x - x^2 and f(x) = x^2 from [0,2] abou

Neko [114]

Answer:

$v = \frac{32\pi}{3}$

$v=33.52$

Step-by-step explanation:

Given

$f(x) = 4x - x^2$

$g(x) = x^2$

$[a,b] = [0,2]$

Required

The volume of the solid formed

Rotating about the x-axis.

Using the washer method to calculate the volume, we have:

$\int dv = \int\limit^b_a \pi(f(x)^2 - g(x)^2) dx$

Integrate

$v = \int\limit^b_a \pi(f(x)^2 - g(x)^2)\ dx$

$v = \pi \int\limit^b_a (f(x)^2 - g(x)^2)\ dx$

Substitute values for a, b, f(x) and g(x)

$v = \pi \int\limit^2_0 ((4x - x^2)^2 - (x^2)^2)\ dx$

Evaluate the exponents

$v = \pi \int\limit^2_0 (16x^2 - 4x^3 - 4x^3 + x^4 - x^4)\ dx$

Simplify like terms

$v = \pi \int\limit^2_0 (16x^2 - 8x^3 )\ dx$

Factor out 8

$v = 8\pi \int\limit^2_0 (2x^2 - x^3 )\ dx$

Integrate

$v = 8\pi [ \frac{2x^{2+1}}{2+1} - \frac{x^{3+1}}{3+1} ]|\limit^2_0$

$v = 8\pi [ \frac{2x^{3}}{3} - \frac{x^{4}}{4} ]|\limit^2_0$

Substitute 2 and 0 for x, respectively

$v = 8\pi ([ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ] - [ \frac{2*0^{3}}{3} - \frac{0^{4}}{4} ])$

$v = 8\pi ([ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ] - [ 0 - 0])$

$v = 8\pi [ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ]$

$v = 8\pi [ \frac{16}{3} - \frac{16}{4} ]$

Take LCM

$v = 8\pi [ \frac{16*4- 16 * 3}{12}]$

$v = 8\pi [ \frac{64- 48}{12}]$

$v = 8\pi * \frac{16}{12}$

Simplify

$v = 8\pi * \frac{4}{3}$

$v = \frac{32\pi}{3}$

$v=\frac{32}{3} * \frac{22}{7}$

$v=\frac{32*22}{3*7}$

$v=\frac{704}{21}$

$v=33.52$

8 0

3 years ago

Write the equation of the line that is parallel to y= 3x -7 and goes through point (4,2).

My name is Ann [436]

Answer:

hi Im Donald J Trump and i approve this message

Step-by-step explanation:

joe biden

6 0

3 years ago

Agustin solved an equation as shown. What error did Agustin make? What is the correct answer?

Hitman42 [59]

Subtract 3/4x from both sides

1/3x-4-3/4x= 3/4x+1-3/4x

-5/12x-4=1

Add 4 to both sides

-5/12x-4+4=1+4

-5/12x=5

Multiply both sides by 12/(-5)

(12/-5)*(-5/12x)= (12/-5)*(5)

x= 12

I hope that's help.

3 0

3 years ago