Answer:
The probability that the coin landed heads is 65.3%.
Step-by-step explanation:
Given : Urn A has 5 white and 17 red balls. Urn B has 9 white and 12 red balls. We flip a fair coin. If the outcome is heads, then a ball from urn A is selected, whereas if the outcome is tails, then a ball from urn B is selected. Suppose that a white ball is selected.
To find : What is the probability that the coin landed heads ?
Solution :
Let the event A be the ball taken from Urn A (5 white and 17 red balls)
Let B=A'- the ball taken from urn B(9 white and 12 red balls)
Let W be event that a white ball is selected.
An urn is chosen based on a toss of a fair coin.
P(A) = coin landed on heads =
P(B) = coin landed on tails =
and
Using Bayes formula,
Therefore, the probability that the coin landed heads is 65.3%.
<h3>
Answer: Less than</h3>
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Explanation:
To convert from a percent to a decimal, move the decimal point over 2 spots to the left
25% = 25.0% converts to 0.25
Think of 0.3 as 0.30
Comparing 0.25 and 0.30, we see that 0.25 is smaller. This is because 25 is smaller than 30.
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Put another way:
0.3 = 0.30 = 30%
We can see that 25% is smaller than 30%
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Whichever method you prefer, 25% is smaller than 0.3
Good morning bre, as to your answers, the hell.
I only answered this so that all of us have more comment space.
Just kidding, I tried to answer it but I couldn't.
Answer:
120.51·cos(377t+4.80°)
Step-by-step explanation:
We can use the identity ...
sin(x) = cos(x -90°)
to transform the second waveform to ...
i₂(t) = 150cos(377t +50°)
Then ...
i(t) = i₁(t) -i₂(t) = 250cos(377t+30°) -150cos(377t+50°)
A suitable calculator finds the difference easily (see attached). It is approximately ...
i(t) = 120.51cos(377t+4.80°)
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The graph in the second attachment shows i(t) as calculated directly from the given sine/cosine functions (green) and using the result shown above (purple dotted). The two waveforms are identical.