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Akimi4 [234]
3 years ago
9

5 \leqslant 5n - 1" align="absmiddle" class="latex-formula">
solve the inequality for n and write the answer in simplest form
Mathematics
1 answer:
ANTONII [103]3 years ago
7 0
Hello there!

n - 5 ≤ 5n - 1

Solve for n

Let's start by subtracting 5n from both sides

n - 5 - 5n ≤ 5n - 5n - 1

n - 5 - 5n ≤ -1

We need to transfer -5 on the other side, we can do that by adding 5 on both sides

n - 5 - 5n + 5 ≤ -1 + 5

n - 5n ≤ -4

-4n ≤ -4

Finally divide both sides by -4

-4n/-4 ≤ -4/-4

n ≥ -1   (This is the answer)!

Do you know why I changed the sign?


 A lot of students failed to remember that rules, which is:
When you are solving an inequality, if you divide both sides by a negative sign, you MUST change the symbol as well. If it was this <, it will change to this >. Got it? Cool!



I hope the steps are clear to understand. If you have questions, feel free to let me know...

As always, I am here to help!
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Pounds gained by persons in your class during the first month of the semester are an example of which type of data?.
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8 0
2 years ago
SHOE COLLECTION: Marquise, Bron'Tavious, and JayDarius each have a shoe collection of Nike Air Vapor Max shoes. Marquise has two
Natasha_Volkova [10]

Answer:

(a) The number of shoes that Marquise has is 40 pairs of shoes

(b) The number of pairs of shoes that Bron'Tavious has is 20 pairs of shoes

(c) The number of pairs of shoes that JayDarius has is 35 pairs of shoes

Step-by-step explanation:

The given information are;

The number of shoes that Marquise has = 2 × The number of pairs of shoes that Bron'Tavious

The number of pairs of shoes that JayDarius has = The number of pairs of shoes that Bron'Tavious + 15

The total number of pairs of shoes they have all together = 95 pairs of shoes

Let the number of pairs of shoes that Bron'Tavious has = X. Therefore, we have;

The number of shoes that Marquise has = 2 × X

The number of pairs of shoes that JayDarius has = X + 15

The total number of pairs of shoes they have all together = X + X + 15 + 2 × X = 95

X + X + 15 + 2 × X = 95

4 × X + 15 = 95

4 × X = 95 - 15 = 80

X = 80/4 = 20

∴ X = 20

(a) The number of shoes that Marquise has = 2 × X = 2 × 20 = 40

The number of shoes that Marquise has = 40 pairs of shoes

(b) The number of pairs of shoes that Bron'Tavious has = X = 20

The number of pairs of shoes that Bron'Tavious has = 20 pairs of shoes

(c) The number of pairs of shoes that JayDarius has = X + 15 = 20 + 15 = 35

The number of pairs of shoes that JayDarius has = 35 pairs of shoes.

5 0
3 years ago
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