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Sergeeva-Olga [200]
3 years ago
13

HELP ASAP WILL MARK BRAINLIEST

Mathematics
1 answer:
nata0808 [166]3 years ago
3 0

Answer:

D

Step-by-step explanation:

Since James gave Malcolm a head start of 20 feet, Malcolm's line should start at 20 feet. So that rules out A. They were obviously going further so they went more feet, So C is ruled out because it shows them not moving, plus James didn't get a 15 foot head start which is what the C graph shows. Finally it's not B because if you look at the key at the bottom of every graph, it says that Malcolm is the dotted line, and B shows James getting a 20 foot head start, not Malcolm.

Hope this helps!

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ASAP!!! ILL GIVE BRAINLIEST
Ostrovityanka [42]

Answer:

The correct options are 2 and 4.

Step-by-step explanation:

From the given box plot it is clear that

\text{Minimum value}=20

Q_1=25

Median=40

Q_3=50

\text{Maximum value}=110

We know that these number divides the data in four equal parts.

Q_1=25\%

Median=50%

Q_3=75\%

25% of the data values lies between 50 and 110. Therefore option 1 is incorrect.

Seventy-five percent of the data values lies between 20 and 50. Therefore option 2 is correct.

It is unlikely that there are any outliers. This statement is not true because the is a huge difference between third quartile and maximum value.

Therefore option 3 is incorrect.

The interquartile range is

IQR=Q_3-Q_1=50-25=25

Therefore option 4 is correct.

The range is

Range = Maximum-Minimum

Range=110-20=90

Therefore option 5 is incorrect.

4 0
3 years ago
A dilation with a scale factor of 15 and centered at the origin is applied to MN¯¯¯¯¯¯¯ with endpoints M(−2, −4) and N(1, 5) .
Nutka1998 [239]
<span>coordinates m' is going to be (-2/5,-4/5)


</span><span>coordinates n' is going to be (1/5,1)

</span>I just took the test i hope this helps!
5 0
3 years ago
Read 2 more answers
We are studying the proportion of cities that have private garbage collector. We want a maximum error of 0.10 and a 95% confiden
True [87]

Answer:

The minimum number of cities we need to contact is 96.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

Z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence interval

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

In this problem, we have that:

p = 0.5, M = 0.1

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.1 = 1.96*\sqrt{\frac{0.5*0.5}{n}}

0.1\sqrt{n} = 0.98

\sqrt{n} = 9.8

(\sqrt{n})^{2} = (9.8)^{2}

n = 96

The minimum number of cities we need to contact is 96.

8 0
2 years ago
No is divisible by 7 if n is divided by 2 3 4 5 the remainder is 1 what is the smallest value that n could b
kvv77 [185]

Answer: 301

Step-by-step explanation:

Since, The LCM of numbers given numbers 2 ,3,  4 and 5 is 60.

Thus, the number that gives 1 as reminder and is the multiple of 7 is  60 n + 1

Where n is any positive integer,

Since, For n = 5,

The number is, 60\times 5 + 1 = 300 + 1 = 301

Which is divisible by 7.

Thus, the required number is 301.

Note : For n = 1, 2 3 and 4, numbers are 61, 121, 181 and 241

But they are not the multiple of 7.

7 0
3 years ago
Read 2 more answers
Help I need it asap
enyata [817]

Answer:

for no 7 its none for 8 its st

Step-by-step explanation:

I hope this helps

8 0
2 years ago
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