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2 years ago

Which expression can be used to find 12 percent of $98?

Mathematics

1 answer:

8090 [49]2 years ago

3 0

Answer:

Step-by-step explanation:

12% is also known as 0.12 which we can multiply by $98 to get the answer.

(hope this helps)

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for positive acute angles A and B it is known that cos A = 40/41 and tan B = 5/12. find the value of sin(A-B) in simplest form

Oxana [17]

Answer:

33/16 hope this helps

Step-by-step explanation:

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2 years ago

Nathan and his brother Zach love to play video games. Right

Monica [59]

Answer:

$N=2Z-11$

$\begin{array}{cc}\text{Zac's score}&\text{Natan's score}\\ 6&1\\7&3\\8&5\\9&7\end{array}$

Step-by-step explanation:

Nathan's score is 11 less than 2 times Zac's score.

Let Z points be Zac's score and N points be Natan's score. then

2 times Zac's score = 2Z

11 less than 2 times Zac's score = 2Z -11

So, N = 2Z - 11

1. If Z=6, then $N=2\cdot 6-11=12-11=1$

2. If Z=7, then $N=2\cdot 7-11=14-11=3$

3. If Z=8, then $N=2\cdot 8-11=16-11=5$

4. If Z=9, then $N=2\cdot 9-11=18-11=7$

Thus, four other possibilities are

$\begin{array}{cc}\text{Zac's score}&\text{Natan's score}\\ 6&1\\7&3\\8&5\\9&7\end{array}$

3 0

3 years ago

Keran works for 85 hours throughout a two-week period. She earns 1,891.25 throughout this period. How much does Karen earn for e

meriva

Answer:

178 is your answer I'm pretty sure

4 0

2 years ago

There are 8 big fish for every___ small fish.

taurus [48]

There are 8 big fish for every 10 small fish, ..... 5 small fish.

4 0

2 years ago

Dubnium-262 has a half-life of 34 s. How long will it take for 500.0 grams to

dmitriy555 [2]

Answer:

the time taken for the radioactive element to decay to 1 g is 304.8 s.

Step-by-step explanation:

Given;

half-life of the given Dubnium = 34 s

initial mass of the given Dubnium, m₀ = 500 grams

final mass of the element, mf = 1 g

The time taken for the radioactive element to decay to its final mass is calculated as follows;

$1 = 500 (0.5)^{\frac{t}{34}} \\\\\frac{1}{500} = (0.5)^{\frac{t}{34}}\\\\log(\frac{1}{500}) = log [(0.5)^{\frac{t}{34}}]\\\\log(\frac{1}{500}) = \frac{t}{34} log(0.5)\\\\-2.699 = \frac{t}{34} (-0.301)\\\\t = \frac{2.699 \times 34}{0.301} \\\\t = 304.8 \ s$

Therefore, the time taken for the radioactive element to decay to 1 g is 304.8 s.

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2 years ago