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3 years ago

Solve proportion 19/11 = f/9

Mathematics

1 answer:

Soloha48 [4]3 years ago

8 0

Answer:

f= 171/11

Step-by-step explanation:

Multiply both sides by 99

19/11*9=f

Simplify 19/11*9 to 171/11

Switch sides

F= 171/11

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The difference between two times six and five

Effectus [21]

Answer:

The difference between 2 × 6 and 2 × 5 is ...

2 × 5 = 10

And,

2 × 6 = 12

So if you subtract 12 - 10

= 2

Therefor, the difference is by 2

* Hopefully this helps:) Mark me the brainliest:)!!

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3 0

3 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used

gladu [14]

Answer:

Part 1) $2x^{2}-32=0----> (-4,4)$

Part 2) $4x^{2}-100=0----> (-5,5)$

Part 3) $x^{2}-55=9----> (-8,8)$

Part 4) $x^{2}-140=-19----> (-11,11)$

Part 5) $2x^{2}-18=0----> (-3,3)$

see the attached figure

Step-by-step explanation:

Solve each quadratic equation

Part 1) we have

$2x^{2}-32=0$

Adds 32 both sides

$2x^{2}=32$

Divide by 2 both sides

$x^{2}=16$

take square root both sides

$x=\pm4$

therefore

The solutions are (-4,4)

Part 2) we have

$4x^{2}-100=0$

Adds 100 both sides

$4x^{2}=100$

Divide by 4 both sides

$x^{2}=25$

take square root both sides

$x=\pm5$

therefore

The solutions are (-5,5)

Part 3) we have

$x^{2}-55=9$

Adds 55 both sides

$x^{2}=9+55$

$x^{2}=64$

take square root both sides

$x=\pm8$

therefore

The solutions are (-8,8)

Part 4) we have

$x^{2}-140=-19$

Adds 140 both sides

$x^{2}=-19+140$

$x^{2}=121$

take square root both sides

$x=\pm11$

therefore

The solutions are (-11,11)

Part 5) we have

$2x^{2}-18=0$

Adds 18 both sides

$2x^{2}=18$

Divide by 2 both sides

$x^{2}=9$

take square root both sides

$x=\pm3$

therefore

The solutions are (-3,3)

7 0

3 years ago

I need help with this question

zvonat [6]

Answer:

Option B is correct

Step-by-step explanation:

Given:

f(x) = -20x^2 +14x +12 and

g(x) = 5x - 6

We need to find f/g and state its domain.

f/g = -20x^2 +14x +12/5x - 6

Taking -2 common from numerator:

f/g = -2(10x^2 - 7x - 6) / 5x -6

Factorize 10x^2 - 7x - 6= 10x^2 - 12x +5x -6

Putting in the above equation

f/g = -2(10x^2 - 12x +5x -6)/ 5x -6

f/g = -2(2x(5x-6) + 1 (5x-6)) / 5x-6

f/g = -2 ( (2x+1)(5x-6))/5x-6

cancelling 5x-6 from numerator and denominator

f/g = -2(2x+1)

f/g = -4x -2

The domain of the function is set of all values for which the function is defined and real.

So, our function g(x) = 5x -6 and domain will be all real numbers except x = 6/5 as denominator will be zero if x=5/6 and the function will be undefined.

So, Option B is correct.

8 0

3 years ago

Read 2 more answers

Solve each quadratic equation. Show your work. 14. (2x – 1)(x + 7) = 0 15. x2 + 3x = 10 16. 4x2 = 100

andreyandreev [35.5K]

14. (2x - 1)(x + 7) = 0

Using the zero factor property, we know that either the first or second terms (or both) must be equal to 0 if their product is 0. We can set each term equal to 0 to find the solutions:

2x - 1 = 0
2x = 1
x = 1/2

x + 7 = 0
x = -7

15. $x^{2} +3x=10$

To solve this equation, you first need to set it equal to 0:

$x^{2} +3x=10 \\ x^{2} +3x-10 = 0$

Next, it can be factored:

$x^{2} +3x-10 = 0 \\ (x+5)(x-2)=0$

Finally, we can solve just like we did above:

x + 5 = 0
x = -5

x - 2 = 0
x = 2

16. $4x^2=100$

First, you can simplify by dividing each side by 4:

$4x^2=100 \\ x^2=25$

Now, set the equation equal to 0:

$x^2=25 \\ x^2-25=0$

Next, factor:

$x^2-25=0 \\ (x+5)(x-5)=0$

Finally, find the solutions:

x + 5 = 0
x = -5

x - 5 = 0
x = 5

6 0

3 years ago

Big Reward! (Answer the right answer not just comment).

Zina [86]

A: One solution- a=11 b=5
B: Has no solution- a=10 b=5
C: Infinite solution- a=10 b=-8

8 0

3 years ago

Read 2 more answers