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marusya05 [52]
3 years ago
6

angle C is a right angle and given the conditions c=2 B= 45 degrees, solve for the side lengths of the right triangle

Mathematics
1 answer:
worty [1.4K]3 years ago
8 0
Since the triangle is 45,45,
90 arrangement. We can use the special triangle trick. Which gives us 2,2 and square root of 2 times 2
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Please help! 15 points to whoever graphs and solves it!
monitta

First you have to get the equation into slope/intercept format: y = mx + b

3y > -3+6x\\\\\frac{3y}{3} >\frac{-3+6x}{3} \\y >\frac{3(-1+2x)}{3} \\y > -1+2x\\\\y>2x-1

So the slope m = 2, and the y-intercept b = -1.

b tells you where the line intersects the y axis. The slope is rise (vertical distance) over run (horizontal distance). I have attached my best attempt at drawing this without graph paper.  The dotted line represents the inequality, and the solution set includes the values above the line which is why it is shaded. Hope this helps!

4 0
3 years ago
Find the value for the side marked below.
KatRina [158]

Answer:

167.7

Step-by-step explanation:

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Lynna [10]
Im not sure what this is, or how to answer it
4 0
3 years ago
5000 is 1/10 of what
umka2103 [35]
5000 is 1/10 of 50000 because 50000 divided by 10 is 5000
8 0
3 years ago
Read 2 more answers
Help with the following problem please
Effectus [21]
Given:
The largest circle has a radius of R=7 units.
Let x be the radius of the large shaded circle.
The small shaded circles have a radius of 1/5 of the large shaded circle.
=> the small shaded circles have a radius of r=x/5

By adding up radii, we have the equation
2(r+x+r)=2(x/5+x+x/5)=2R=2*7=14
Simplify:
7x/5=14/2
x=5
=> r=1

Area of outer circle                  = \pi R^2=\pi7^2=49\pi
Area of large shaded circle      = \pi x^2=\pi5^2=25\pi
Area of 4 small shaded circles = 4\pi r^2=4\pi1^2=4\pi
Total area of shaded circles     =25\pi+4\pi=29\pi

Shaded area as a fraction of that of the outer circle 
=\frac{29\pi}{49\pi}=29/49

3 0
2 years ago
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