The cube root of 2744000 is 140
Answer:
all work is shown and pictured
AC is perpendicular to BD.
<h3>
Further explanation</h3>
- We observe that both the ABC triangle and the ADC triangle have the same AC side length. Therefore we know that is reflexive.
- The length of the base of the triangle is the same, i.e., .
- In order to prove the triangles congruent using the SAS congruence postulate, we need the other information, namely . Thus we get ∠ACB = ∠ACD = 90°.
Conclusions for the SAS Congruent Postulate from this problem:
- ∠ACB = ∠ACD
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The following is not other or additional information along with the reasons.
- ∠CBA = ∠CDA no, because that is AAS with ∠ACB = ∠ACD and
- ∠BAC = ∠DAC no, because that is ASA with and ∠ACB = ∠ACD.
- no, because already marked.
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Notes
- The SAS (Side-Angle-Side) postulate for the congruent triangles: two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle; the included angle properly represents the angle formed by two sides.
- The ASA (Angle-Side-Angle) postulate for the congruent triangles: two angles and the included side of one triangle are congruent to two angles and the included side of another triangle; the included side properly represents the side between the vertices of the two angles.
- The SSS (Side-Side-Side) postulate for the congruent triangles: all three sides in one triangle are congruent to the corresponding sides within the other.
- The AAS (Angle-Angle-Side) postulate for the congruent triangles: two pairs of corresponding angles and a pair of opposite sides are equal in both triangles.
<h3>Learn more</h3>
- Which shows two triangles that are congruent by ASA? brainly.com/question/8876876
- Which shows two triangles that are congruent by AAS brainly.com/question/3767125
- About vertical and supplementary angles brainly.com/question/13096411
Answer:
Step-by-step explanation:
(2x−12)^2 can be factored into 2^2*(x - 6)^2, which in turn becomes
4(x^2 - 12x + 36). Yes, this is a special product of the form
(a - b)^2 = a^2 - 2ab + b^2.