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tiny-mole [99]
3 years ago
13

Simplify completely: 3 4i

Mathematics
2 answers:
e-lub [12.9K]3 years ago
7 0

The correct answer to simplify 3/4i is -3i/4

drek231 [11]3 years ago
4 0
3/4 is already simplified<span> completely.</span>
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Help please i will give brainlest
Anton [14]

Your answer is B. 3 13/24

Hoped this helped :)

Have a wonderful day-

8 0
2 years ago
Read 2 more answers
n △ABC, point P∈ AB is so that AP:BP=1:3 and point M is the midpoint of segment CP. Find the area of △ABC if the area of △BMP is
monitta

Answer: The area of ABC is 56 m².

Explanation:

It is given that in △ABC, point P∈ AB is so that AP:BP=1:3 and point M is the midpoint of segment CP.

Since point P divides the line AB in 1:3, therefore the area of triangle APC and BPC is also in ratio 1:3. To prove this draw a perpendicular h on AB from C.

\frac{\text{Area of } \triangle BCP}{\text{Area of } \triangle ABC} =\frac{\frac{1}{2}\times BP\times CH}{\frac{1}{2}\times AB\times CH} =\frac{BP}{AB}= \frac{3}{4}

Since the area of BPC is \frac{3}{4}th part of total area, therefore area of APC is  \frac{1}{4}th part of total area.

The point M is the midpoint of CP, therefore the area of BMP and BMC is equal by midpoint theorem.

\text{Area of } \triangle BMP=\text{Area of } \triangle BMC

21=\text{Area of } \triangle BMC

Area of BPC is,

\text{Area of } \triangle BPC=\text{Area of } \triangle BMP+\text{Area of } \triangle BMC

\text{Area of } \triangle BPC=21+21

\text{Area of } \triangle BPC=42

Area of APC is,

\text{Area of } \triangle APC=\frac{1}{3}\times \text{Area of } \triangle BPC

\text{Area of } \triangle APC=\frac{1}{3}\times 42

\text{Area of } \triangle APC=14

Area of ABC is,

\text{Area of } \triangle ABC=\text{Area of } \triangle APC+\text{Area of } \triangle BPC

\text{Area of } \triangle ABC=14+42=56

Therefore, the area of ABC is 56 m².

5 0
3 years ago
*BRAINLIEST* The graphs below have the same shape. Complete the equation of the blue graph.​
PIT_PIT [208]

Answer:

(x-2)^2

Step-by-step explanation:

The blue graph is shifted two units to the right of the "original" function x^2 (red). Let's recall the vertex form of a quadratic:

a (x-h)^2 + k

where a represents a constant that describes the opening of the parabola (up/down); h represents horizontal shift; and k represents vertical shift.

The blue graph is two units to the right (+2), there is NO vertical shift and NO change in how the parabola opens.

So, let's plug the appropriate values into vertex form:

(x-(+2))^2

= (x-2)^2

5 0
3 years ago
WILL MARK BRAINLIEST!!!!
vampirchik [111]

Answer:

1978$

Step-by-step explanation:

Hope you day is going well!

5 0
4 years ago
Most quadratic equations have______roots?
ElenaW [278]

Answer:

equal

Step-by-step explanation:

Most quadratic equations have <em>equal</em> roots.

5 0
3 years ago
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