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Answer: The area of ABC is 56 m².
Explanation:
It is given that in △ABC, point P∈ AB is so that AP:BP=1:3 and point M is the midpoint of segment CP.
Since point P divides the line AB in 1:3, therefore the area of triangle APC and BPC is also in ratio 1:3. To prove this draw a perpendicular h on AB from C.

Since the area of BPC is
th part of total area, therefore area of APC is
th part of total area.
The point M is the midpoint of CP, therefore the area of BMP and BMC is equal by midpoint theorem.


Area of BPC is,



Area of APC is,



Area of ABC is,


Therefore, the area of ABC is 56 m².
Answer:
(x-2)^2
Step-by-step explanation:
The blue graph is shifted two units to the right of the "original" function x^2 (red). Let's recall the vertex form of a quadratic:
a (x-h)^2 + k
where a represents a constant that describes the opening of the parabola (up/down); h represents horizontal shift; and k represents vertical shift.
The blue graph is two units to the right (+2), there is NO vertical shift and NO change in how the parabola opens.
So, let's plug the appropriate values into vertex form:
(x-(+2))^2
= (x-2)^2
Answer:
1978$
Step-by-step explanation:
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Answer:
equal
Step-by-step explanation:
Most quadratic equations have <em>equal</em> roots.