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PtichkaEL [24]
3 years ago
15

Please help? I need the answer quick!

Mathematics
1 answer:
Daniel [21]3 years ago
6 0

Answer:

sorry icant open the picture my phone is lagging

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What is the surface area?<br> 5 mm<br> 4 mm<br> 5 mm<br> 6 mm<br> 7 mm<br> square millimeters
postnew [5]

Answer:

136 square millimeters

Step-by-step explanation:

4 0
3 years ago
To solve this system of equations by elimination, what operation could be used to eliminate the x-variable and find the value of
stepan [7]

Answer:

see explanation

Step-by-step explanation:

Given the 2 equations

- 6x - 4y = 2 → (1)

- 4x - 7y = 2 → (2)

Multiplying (1) by 4 and (2) by - 6 will eliminate the x- term

- 24x - 16y = 8 → (3)

24x + 42y = - 12 → (4)

Add (3) and (4) term by term

26y = - 4 ( divide both sides by  26 )

y = \frac{-4}{26} = - \frac{2}{13}

7 0
3 years ago
What is 789 times 26372
Rus_ich [418]

Answer:

20807508

Step-by-step explanation:20807508

8 0
3 years ago
The graph of the function f(x) = –(x + 6)(x + 2) is shown below.
schepotkina [342]

Answer:

a. The function is increasing for all real values of x where  x < –4.

Step-by-step explanation:

Let me help you, I have answered this question once in Brainly as well

Given the factored form of the function:

f(x) = -(x + 6)(x+2)

<=> f(x) = -x^{2} - 8x -12

We will convert to vertex form

f(x) = -(x+4)^{2} + 4

Let analyse other possible answers:

<u>a. The function is increasing for all real values of x where  x < –4.</u>

True, because  the parameter a = - 1 so the graph open down all over its domain

<u>b. The function is increasing for all real values of x where  –6 < x < –2.</u>

Wrong, the function decrease in the interval from –4.< x < -2

<u>c. The function is decreasing for all real values of x where  x < –6 and where x > –2.</u>

Wrong, the function increase in the interval from -6 < x < -4

<u>d. The function is decreasing for all real values of x where  x < –4.</u>

Wrong,  The function is increasing  for all real values of x where  x < –4.

7 0
3 years ago
Read 2 more answers
Help with set module 3 secondary math 3 3.3
sineoko [7]

Answer/Step-by-step explanation:

7. (3x⁴ + 5x² - 1) + (2x³ + x)

Distribute +1 to each term in the parentheses by your right.

3x⁴ + 5x² - 1 + 2x³ + x

Rewrite in standard form

3x⁴ + 2x¾ + 5x² + x - 1

8. (4x² + 7x - 4) + (x² - 7x + 14)

Distribute +1 to each term in the parentheses by your right.

4x² + 7x - 4 + x² - 7x + 14

Collect like terms and add together

4x² + x² + 7x - 7x - 4 + 14

5x² + 10

9. (2x³ + 6x² - 5x) + (x⁵ + 3x² + 8x + 4)

2x³ + 6x² - 5x + x⁵ + 3x² + 8x + 4

Collect like terms and add together

2x³ + 6x² + 3x² - 5x + 8x + x⁵ + 4

2x³ + 9x² + 3x + x⁵ + 4

Rewrite in standard form

x⁵ + 2x³ + 9x² + 3x + 4

10. (-6x⁵ - 2x + 13) + (4x⁵ + 3x² + x - 9)

-6x⁵ - 2x + 13 + 4x⁵ + 3x² + x - 9

Collect like terms

-6x⁵ + 4x⁵ - 2x + x + 13 - 9 + 3x²

Add like terms

-2x⁵ - x + 4 + 3x²

Rewrite in standard form

-2x⁵ + 3x² - x + 4

11. (5x² + 7x + 2) - (3x² + 6x + 2)

Distribute -1 to each term in the parentheses by your right.

5x² + 7x + 2 - 3x² - 6x - 2

Collect like terms

5x² - 3x² + 7x - 6x + 2 - 2

2x² + x

12. (10x⁴ + 2x² + 1) - (3x⁴ + 3x + 11)

Distribute -1 to each term in the parentheses by your right.

10x⁴ + 2x² + 1 - 3x⁴ - 3x - 11

Collect like terms

10x⁴ - 3x⁴ + 2x² + 1 - 11 - 3x

7x⁴ + 2x² - 10 - 3x

Rewrite in standard form

7x⁴ + 2x² - 3x - 10

13. (7x³ - 3x + 7) - (4x² - 3x - 11)

Distribute -1 to each term in the parentheses by your right.

7x³ - 3x + 7 - 4x² + 3x + 11

Collect like terms

7x³ - 3x + 3x + 7 + 11 - 4x²

7x³ + 18 - 4x²

Rewrite in standard form

7x³ - 4x² + 18

14. (x⁴ - 1) - (x⁴ + 1)

Distribute -1 to each term in the parentheses by your right.

x⁴ - 1 - x⁴ - 1

Collect like terms

x⁴ - x⁴ - 1 - 1

-2

8 0
3 years ago
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