Question

A copper tube with mass 100g and 10cm long contains a current of 1A running through to the right. A magnetic field is turned on going forward ("into the board") with a strength of 1T. In grams, rounded to the nearest tenth, what will the scale read? (Note: the scale will read whatever force it needs to use to balance the tube divided by g = 9.81 m/s^2)

Answer 1

Answer:

Scale reading will be 0.098            

Explanation:

We have given mass of the copper tube m = 100 gram = 0.1 kg

Length of the copper tube L = 10 cm = 0.1 m

Magnetic field B = 1 T

Current flowing through copper tube i = 1 A

Acceleration due to gravity $g=9.81m/sec^2$

Gravitational force on the copper tube = mg = 0.1 ×9.81 = 0.981 N

Magnetic force on the copper tube = iBL = 1×1×0.1 = 0.1 N

So balancing force F = 0.981-0.1 = 0.881

We have given that scale reading will be balancing force divided by g

So scale reading $=\frac{0.881}{9.81}=\frac{0.881}{9.81}=0.098$