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Lera25 [3.4K]
3 years ago
13

What is the kinetic energy of an object that has a mass of 12 kilograms and moves with a velocity of 10 m/s?

Physics
2 answers:
Alik [6]3 years ago
3 0
1/2mv^2

1/2x12x10^2=600J

The kinetic energy is 600J
Katena32 [7]3 years ago
3 0

Answer:

The kinetic energy of the object is 600 J

Explanation:

It is given that,

Mass of the object, m = 12 kg

Velocity of the object, v = 10 m/s

Kinetic energy of the object is given by :

E=\dfrac{1}{2}mv^2

E=\dfrac{1}{2}\times 12\times (10)^2

E = 600 J

So, the kinetic energy of the object is 600 J. Hence, this is the required solution.

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(11) The speed of radio waves is 300 000 000 m/s.
Neko [114]

Answer:

Wavelength = 9.68 meters

Explanation:

Given the following data;

Speed = 300,000,000m/s

Frequency = 31 Megahertz to Hertz = 31 * 10⁶ Hz

To find the wavelength;

Wavelength = speed/frequency

Wavelength = 300,000,000/31,000,000

Wavelength = 9.68 meters

7 0
2 years ago
Which is an example of a covalent bond?
velikii [3]
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4 0
3 years ago
If a longitudinal wave passes a specific point seven times per second, and the distance between wave rarefaction points is 2 met
zavuch27 [327]

Answer: 14 m/s

Explanation:

The speed S of a sound wave is given by the following equation:

S=\lambda f

Where:

\lambda=2 m is the wavelength of the sound wave

f=7 times/s=7 Hz

S=(2 m)(7 Hz)

Hence:

S=14 m/s

4 0
3 years ago
A boat leaves the dock at t = 0.00 s and, starting from rest, maintains a constant acceleration of (0.461 m/s2)i relative to the
liberstina [14]

Answer:

At t=4.82 s, the boat is moving at 3.464 m/s.

At t=4.82 s, the boat is 13.112 m from the dock.

Explanation:

The speed of the boat in j'th direction remains constant for all times (vj=2.16 m/s), however, the speed in i'th direction is changing due to the constant acceleration (0.461 m/s^2)i.

In order to find the velocity of the boat a t=4.82 s, first we need to compute the velocity of the boat relative to the water in the i direction (vi_b) at t=4.82 s:

vi_b = a*t = (0.461 m/s^2)*(4.82 s) = 2.222 m/s

Now, we add this velocity to the velocity of the water in the i direction:

vi = vi_b + vi_w = 2.222 m/s + 0.486 m/s = 2.708 m/s

Therefore, the speed of the boat at t = 4.82 s is: v = (vi, vj) = (2.708, 2.16) m/s. Finally, to find its speed, we just calculate the magnitude of v and obtain that the speed is: 3.464 m/s.

For the second question, first we will find the distance that the boat moved in the i'th direction and then in the j'th direction.

The speed in the i'th direction, for all times, is given by:

(0.485 + 0.461*t) and in order to find the distance advanced in the i'th direction (di) during 4.82 s, we need to integrate this velocity:

di = 0.485*t + (0.461*t^2)/2 (evaluated from t=0 to t =4.82) = 0.485*(4.82) + (0.461*(4.82)^2)/2 = 2.337 + 5.634 = 7.971 m

The speed in j'th direction, for all times, is given by:

2.16 and in order to find the distance advanced in the j'th direction (dj) during 4.82 s, we need to integrate this velocity:

dj = 2.16*t (evaluated from t=0 to t =4.82) = (2.16)*(4.82) = 10.411 m

Using Pythagoras' Theorem, we find that the the boat is at 13.112 m from the dock at t = 4.82 s.

4 0
2 years ago
Los huracanes y tornados se producen por las corrientes de convencion
Montano1993 [528]

Answer:

correct!

Explanation:

4 0
3 years ago
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