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3 years ago

What is the kinetic energy of an object that has a mass of 12 kilograms and moves with a velocity of 10 m/s?

Physics

2 answers:

Alik [6]3 years ago

3 0

1/2mv^2

1/2x12x10^2=600J

The kinetic energy is 600J

Katena32 [7]3 years ago

3 0

Answer:

The kinetic energy of the object is 600 J

Explanation:

It is given that,

Mass of the object, m = 12 kg

Velocity of the object, v = 10 m/s

Kinetic energy of the object is given by :

$E=\dfrac{1}{2}mv^2$

$E=\dfrac{1}{2}\times 12\times (10)^2$

E = 600 J

So, the kinetic energy of the object is 600 J. Hence, this is the required solution.

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4 years ago

A 0.453 kg pendulum bob passes through the lowest part of its path at a speed of 2.58 m/s. What is the tension in the pendulum c

harkovskaia [24]

Answer with Explanation:

Mass of pendulum bob, m=0.453 kg

Speed, $v_1=$ 2.58 m/s

a.r=75.1 cm= $75.1\times 10^{-2}m$ =0.751 m

$1cm=10^{-2} m$

Tension in the pendulum cable is given by

Tension=Centripetal force+force due to gravity

$T=\frac{mv^2}{r}+mg$

Where $g=9.8 m/s^2$

Substitute the values

$T=\frac{0.453(2.58)^2}{75.1\times 10^{-2}}+0.453\times 9.8$

$T=8.45 N$

b.When the pendulum reaches its highest point,then

Final velocity, $v_2=0$

According to law of conservation of energy

$mgh_1+\frac{1}{2}mv^2_1=mgh_2+\frac{1}{2}mv^2_2$

$gh_1+\frac{1}{2}v^2_1=gh_2+\frac{1}{2}v^2_2$

$h_1=0$

Substitute the values

$9.8\times 0+\frac{1}{2}(2.58)^2=9.8\times h_2+\frac{1}{2}(0)^2$

$3.3282=9.8h_2$

$h_2=\frac{3.3282}{9.8}=0.34 m$

The angle mad by cable with the vertical= $cos\theta=\frac{0.751-0.34}{0.751}=0.55$

$\theta=cos^{-1}(0.55)=56.6^{\circ}$

c.When the pendulum reaches at highest point then

Acceleration, a=0

Therefore, the tension in the pendulum cable

$T=mgcos\theta$

Substitute the values

$T=0.453\times 9.8cos56.6$

$T=2.4 N$

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