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Lera25 [3.4K]
3 years ago
13

What is the kinetic energy of an object that has a mass of 12 kilograms and moves with a velocity of 10 m/s?

Physics
2 answers:
Alik [6]3 years ago
3 0
1/2mv^2

1/2x12x10^2=600J

The kinetic energy is 600J
Katena32 [7]3 years ago
3 0

Answer:

The kinetic energy of the object is 600 J

Explanation:

It is given that,

Mass of the object, m = 12 kg

Velocity of the object, v = 10 m/s

Kinetic energy of the object is given by :

E=\dfrac{1}{2}mv^2

E=\dfrac{1}{2}\times 12\times (10)^2

E = 600 J

So, the kinetic energy of the object is 600 J. Hence, this is the required solution.

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What is the mass of a stone moving at a speed of 15 meters/second and having a momentum of 7.5 kilogram - meters / seconds
Elanso [62]

Answer:

0.5 kg

Explanation:

The momentum of an object is defined as

p = mv

where

m is the mass

v is the velocity

In this problem we have,

v = 15 m/s is the velocity of the stone

p = 7.5 kg m/s is the momentum

Solving for m, we can find the mass of the stone:

m=\frac{p}{v}=\frac{7.5 kg m/s}{15 m/s}=0.5 kg

4 0
3 years ago
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If the half-life of niobium-91 is 680 years, how long will it take for the decay described in the previous question?
Svet_ta [14]
2040

15.4+2.2/2 until it equals 2.2
( divide by 3)

680(years)*3 devisions = 2040
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3 years ago
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Tim made tomato soup from scratch. When he cleaned up, he noticed that the aluminum pan was damaged. Analyze what happened to th
mr_godi [17]

Answer:

D) The acidic tomato juice reacted unfavorably with the aluminum pan

5 0
3 years ago
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At a certain instant, the earth, the moon, and a stationary 1160 kg spacecraft lie at the vertices of an equilateral triangle wh
Afina-wow [57]

Answer:

W = 1.22 \times 10^9 J

Explanation:

Initial potential energy of the given spacecraft is given as

U = -\frac{GM_e m}{r} - \frac{GM_m m}{r}

so we have

U = - \frac{Gm}{r}(M_e + M_m)

so we have

M_e = 5.98 \times 10^{24} kg

M_m = 7.35 \times 10^{22} kg

m = 1160 kg

r = 3.84 \times 10^8 m

U = - \frac{(6.67 \times 10^{-11})(1160)}{3.84 \times 10^8}(5.98 \times 10^{24} + 7.35 \times 10^{22})

U = -1.22 \times 10^9 J

now total work done to move it to infinite is given

W = 0 - U

W = 1.22 \times 10^9 J

6 0
3 years ago
01:28:29
Novosadov [1.4K]

Answer:

an inverse relationship

7 0
3 years ago
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