You know that the discrete metric only takes values of 1 and 0. Now suppose it comes from some norm ||.||. Then for any α in the underlying field of your vector space and x,y∈X, you must have that
∥α(x−y)∥=|α|∥x−y∥.
But now ||x−y|| is a fixed number and I can make α arbitrarily large and consequently the discrete metric does not come from any norm on X.
Step-by-step explanation:
hope this helps
Answer:
the second one is your answer
Step-by-step explanation:
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Make slope intercept
3x - y = 5
3x = y + 5
y = 3x - 5
Parallel = same slope
Slope = 3
Y = 3x + b
Plug in the point
-2 = 3(-1) + b
-2 = -3 + b, b = 1
Solution: y = 3x + 1
Answer:
Step-by-step explanation:
2in by 2in by 3in
if each cube is 1/2 edge length then
4 by 4 by 6
4x4x6
16x6
96
96 cubes are needed
